Explanation The required reaction is given below. C l 2 ( g ) + B r 2 ( g ) ⇌ 2 B r C l ( g ) , K c = 0.031 The expression for equilibrium constant for the above reaction can be written as shown below, K c = [ B r C l ] 2 [ C l 2 ] [ B r 2 ] Given that, the equilibrium concentration of C l 2 a n d B r C l is 0.495 m o l . L − 1 a n d 0.145 m o l . L − 1 respectively. By rearranging the above expression, the equilibrium concentration of B r 2 can be calculated as shown below. K c = [ B r C l ] 2 [ C l 2 ] [ B r 2 ] <

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ISBN: 9781319086411

Author: ATKINS

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Chapter 5, Problem 5I.1E

Interpretation Introduction

Interpretation:

The equilibrium molar concentration of Br2 for the given below reaction has to be calculated.

Cl2(g)+Br2(g)⇌ 2BrCl(g), Kc=0.031

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Chapter 5, Problem 5I.4BST

Chapter 5, Problem 5I.2E

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Chapter 5 Solutions

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The equilibrium molar concentration of B r 2 for the given below reaction has to be calculated. C l 2 ( g ) + B r 2 ( g ) ⇌ 2 B r C l ( g ) , K c = 0.031

Solution Summary: The author explains the equilibrium molar concentration of Br_2 for the given below reaction.

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Interpretation:

The equilibrium molar concentration of Br2 for the given below reaction has to be calculated.

Cl2(g)+Br2(g)⇌ 2BrCl(g), Kc=0.031

Want to see the full answer?

Chapter 5 Solutions

The equilibrium molar concentration of B r 2 for the given below reaction has to be calculated. C l 2 ( g ) + B r 2 ( g ) ⇌ 2 B r C l ( g ) , K c = 0.031

Solution Summary: The author explains the equilibrium molar concentration of Br_2 for the given below reaction.

Videos

Interpretation: The equilibrium molar concentration of Br2 for the given below reaction has to be calculated. Cl2(g)+Br2(g)⇌ 2BrCl(g), Kc=0.031

Want to see the full answer?

Chapter 5 Solutions

Interpretation:

The equilibrium molar concentration of Br2 for the given below reaction has to be calculated.

Cl2(g)+Br2(g)⇌ 2BrCl(g), Kc=0.031