Chemistry: Atoms First
Chemistry: Atoms First
3rd Edition
ISBN: 9781259638138
Author: Julia Burdge, Jason Overby Professor
Publisher: McGraw-Hill Education
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Chapter 5, Problem 5.68QP

(a)

Interpretation Introduction

Interpretation: The molecular mass/formula mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.  The sum of the atomic masses of individual atoms present in a formula unit will be termed as formula mass, it may or may not be a formula of molecule.

(a)

Expert Solution
Check Mark

Answer to Problem 5.68QP

Molecular mass of BrN3=121.925amu

Explanation of Solution

To calculate: Molecular mass of BrN3

Molecular formula is given as BrN3

MolecularmassofBrN3=1(massofBrinamu)+3(massofNinamu)=1(79.904amu)+3(14.007amu)=(79.904+42.021)amu=121.925amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of BrN3 was found to be 121.925amu.

(b)

Interpretation Introduction

Interpretation: The molecular mass/formula mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.  The sum of the atomic masses of individual atoms present in a formula unit will be termed as formula mass, it may or may not be a formula of molecule.

(b)

Expert Solution
Check Mark

Answer to Problem 5.68QP

Molecular mass of C4H10=58.1218amu

Explanation of Solution

To calculate: Molecular mass of C4H10

Molecular formula is given as C4H10

MolecularmassofC4H10=4(massofCinamu)+10(massofHinamu)=4(12.0107amu)+10(1.0079amu)=(48.0428+10.079)amu=58.1218amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of C4H10 was found to be 58.1218amu.

(c)

Interpretation Introduction

Interpretation: The molecular mass/formula mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.  The sum of the atomic masses of individual atoms present in a formula unit will be termed as formula mass, it may or may not be a formula of molecule.

(c)

Expert Solution
Check Mark

Answer to Problem 5.68QP

Molecular mass of NI3=394.72041amu

Explanation of Solution

To calculate: Molecular mass of NI3

Molecular formula is given as NI3

MolecularmassofNI3=1(massofNinamu)+3(massofIinamu)=1(14.007amu)+3(126.90447amu)=(14.007+380.71341)amu=394.72041amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of NI3 was found to be 394.72041amu.

(d)

Interpretation Introduction

Interpretation: The molecular mass/formula mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.  The sum of the atomic masses of individual atoms present in a formula unit will be termed as formula mass, it may or may not be a formula of molecule.

(d)

Expert Solution
Check Mark

Answer to Problem 5.68QP

Formula mass of Al2S3=150.158amu

Explanation of Solution

To calculate: Formula mass of Al2S3

Molecular formula is given as Al2S3

FormulamassofAl2S3=2(massofAlinamu)+3(massofSinamu)=2(26.9815amu)+3(32.065amu)=(53.963+96.195)amu=150.158amu

The formula mass of the given substance was calculated using atomic weights of each elements present in its formula unit.  The molecular mass of Al2S3 was found to be 150.158amu.

(e)

Interpretation Introduction

Interpretation: The molecular mass/formula mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.  The sum of the atomic masses of individual atoms present in a formula unit will be termed as formula mass, it may or may not be a formula of molecule.

(e)

Expert Solution
Check Mark

Answer to Problem 5.68QP

Formula mass of Fe(NO3)2=179.8548amu

Explanation of Solution

To calculate: Formula mass of Fe(NO3)2

Molecular formula is given as Fe(NO3)2

FormulamassofFe(NO3)2=1(massofFe)+2(1(massofNinamu)+3(massofOinamu))=55.845amu+2(14.0067+3(15.9994))amu=55.845amu+2(14.0067+47.9982)amu=55.845amu+2(62.0049)amu                                            =(55.845+124.0098)amu=179.8548amu

The formula mass of the given substance was calculated using atomic weights of each elements present in its formula unit.  The molecular mass of Fe(NO3)2 was found to be 179.8548amu.

(f)

Interpretation Introduction

Interpretation: The molecular mass/formula mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.  The sum of the atomic masses of individual atoms present in a formula unit will be termed as formula mass, it may or may not be a formula of molecule.

(f)

Expert Solution
Check Mark

Answer to Problem 5.68QP

Molecular mass of PCl3=137.3328amu

Explanation of Solution

To calculate: Molecular mass of PCl3

Molecular formula is given as PCl3

MolecularmassofPCl3=1(massofPinamu)+3(massofClinamu)=1(30.9738amu)+3(35.453amu)=(30.9738+106.359)amu=137.3328amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of PCl3 was found to be 137.3328amu.

(g)

Interpretation Introduction

Interpretation: The molecular mass/formula mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.  The sum of the atomic masses of individual atoms present in a formula unit will be termed as formula mass, it may or may not be a formula of molecule.

(g)

Expert Solution
Check Mark

Answer to Problem 5.68QP

Molecular mass of (NH4)2CO3=96.0855amu

Explanation of Solution

To calculate: Molecular mass of (NH4)2CO3

Molecular formula is given as (NH4)2CO3

Molecularmassof(NH4)2CO3=2((massofNinamu)+4(massofHinamu))+1(massofCinamu)+3(massofOinamu)=(2(14.0067+4(1.0079))+1(12.0107)+3(15.9994))amu=(2(14.0067+4.0316)+12.0107+47.9982)amu=(2(18.0383)+12.0107+47.9982)amu                                                  =(36.0766+12.0107+47.9982)amu=96.0855amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of (NH4)2CO3 was found to be 96.0855amu.

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Chapter 5 Solutions

Chemistry: Atoms First

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