General Chemistry: Atoms First
General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Chapter 5, Problem 5.57SP

(a)

Interpretation Introduction

Interpretation:

The bond order of O2 has to be determined.

Concept introduction:

Bond order:

  • Bond order is nothing but the number of chemical bonds that involved in between a pair of atoms.
  • Bond order indicates the stability of a bond and it reflects the stability of the molecule.
  • An element having bond order zero value is not exit in the universe, but compounds may have a bond order of zero.
  • According to molecular orbital theory bond order can be calculated by using the following formula.

B.O =number of bonding electrons - number of antibonding electrons2

(b)

Interpretation Introduction

Interpretation:

The requirement of electrons to increase the bond order of O2 molecule has to be given.

Concept introduction:

Bond order:

  • Bond order is nothing but the number of chemical bonds that involved in between a pair of atoms.
  • Bond order indicates the stability of a bond and it reflects the stability of the molecule.
  • An element having bond order zero value is not exit in the universe, but compounds may have a bond order of zero.
  • According to molecular orbital theory bond order can be calculated by using the following formula.

B.O =number of bonding electrons - number of antibonding electrons2

(c)

Interpretation Introduction

Interpretation:

The charge and bond order of the new species made in part (b) can be determined.

Concept introduction:

Bond order:

  • Bond order is nothing but the number of chemical bonds that involved in between a pair of atoms.
  • Bond order indicates the stability of a bond and it reflects the stability of the molecule.
  • An element having bond order zero value is not exit in the universe, but compounds may have a bond order of zero.
  • According to molecular orbital theory bond order can be calculated by using the following formula.

B.O =number of bonding electrons - number of antibonding electrons2

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Chapter 5 Solutions

General Chemistry: Atoms First

Ch. 5.4 - Identify each of the following sets of hybrid...Ch. 5.4 - The following ball-and-stick molecular model is a...Ch. 5.5 - Construct an MO diagram for the He2+ ion. Is this...Ch. 5.6 - The B2 and C2 molecules have MO diagrams similar...Ch. 5.7 - Draw two electron-dot resonance structures for the...Ch. 5.7 - Why is molecular shape so important in biological...Ch. 5.7 - Prob. 5.17CPCh. 5 - What is the geometry around the central atom in...Ch. 5 - Prob. 5.19CPCh. 5 - Prob. 5.20CPCh. 5 - Prob. 5.21CPCh. 5 - Prob. 5.22CPCh. 5 - Prob. 5.23CPCh. 5 - Prob. 5.24SPCh. 5 - Prob. 5.25SPCh. 5 - Prob. 5.26SPCh. 5 - How many charge clouds are there around central...Ch. 5 - Prob. 5.28SPCh. 5 - Prob. 5.29SPCh. 5 - What shape do you expect for each of the following...Ch. 5 - Prob. 5.31SPCh. 5 - Prob. 5.32SPCh. 5 - Prob. 5.33SPCh. 5 - What bond angles do you expect for each of the...Ch. 5 - Prob. 5.35SPCh. 5 - Prob. 5.36SPCh. 5 - Prob. 5.37SPCh. 5 - Prob. 5.38SPCh. 5 - A potential replacement for the chlorofluorocarbon...Ch. 5 - Prob. 5.40SPCh. 5 - Prob. 5.41SPCh. 5 - Prob. 5.42SPCh. 5 - Prob. 5.43SPCh. 5 - What hybridization do you expect for atoms that...Ch. 5 - Prob. 5.45SPCh. 5 - Prob. 5.46SPCh. 5 - What hybridization would you expect for the...Ch. 5 - Prob. 5.48SPCh. 5 - Prob. 5.49SPCh. 5 - Prob. 5.50SPCh. 5 - Prob. 5.51SPCh. 5 - Prob. 5.52SPCh. 5 - Prob. 5.53SPCh. 5 - Prob. 5.54SPCh. 5 - Prob. 5.55SPCh. 5 - Prob. 5.56SPCh. 5 - Prob. 5.57SPCh. 5 - Prob. 5.58SPCh. 5 - Prob. 5.59SPCh. 5 - Prob. 5.60SPCh. 5 - Prob. 5.61SPCh. 5 - Prob. 5.62CHPCh. 5 - The following molecular model is a representation...Ch. 5 - Prob. 5.64CHPCh. 5 - Prob. 5.65CHPCh. 5 - Prob. 5.66CHPCh. 5 - Prob. 5.67CHPCh. 5 - Calcium carbide, CaC2, reacts with water to...Ch. 5 - Prob. 5.69CHPCh. 5 - The N2O5 molecule has six NO bonds and two NO ...Ch. 5 - In the cyanate ion, OCN, carbon is the central...Ch. 5 - Aspirin has the following connections among atoms....Ch. 5 - Prob. 5.73CHPCh. 5 - At high temperatures, sulfur vapor is...Ch. 5 - Carbon monoxide is produced by incomplete...Ch. 5 - Prob. 5.76CHPCh. 5 - Prob. 5.77CHPCh. 5 - Prob. 5.78CHPCh. 5 - The diatomic cyanide ion (CN) and nitrosonium ion...Ch. 5 - Prob. 5.80MPCh. 5 - Prob. 5.81MPCh. 5 - Prob. 5.82MP
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