
Concept explainers
(a)
Interpretation:
The total number of electron dots that is present in
Concept Introduction:
Lewis structure clearly depicts the bonding and nonbonding electrons in the atom. This is only partially useful for the molecule that contains one or more multiple bonds and when coordinate covalent bond is present in the molecule. For drawing Lewis structure a systematic procedure is followed. They are,
- The total number of valence electrons that is present in molecule is calculated by adding all the valence electrons of the atoms present in the molecule.
- The chemical symbols for the atoms that is present in the molecule is written in the order that they are bonded. After this a single covalent bond is placed between each atoms as two electrons.
- The nonbonding electrons are added to each atom that is bonded to the central atom so that it contains octet of electrons. For hydrogen alone the “octet” is only two electrons.
- The remaining electrons has to be placed on the central atom in the structure.
- If there is no octet of electrons present in the central atom, then use one or more pairs of nonbonding electrons that is bonded to the central atom to form double or triple bonds.
- The total number of electrons has to be counted and it has to be confirmed whether the count is same as that of the number of valence electrons that is available for bonding.
(b)
Interpretation:
The total number of electron dots that is present in
Concept Introduction:
Lewis structure clearly depicts the bonding and nonbonding electrons in the atom. This is only partially useful for the molecule that contains one or more multiple bonds and when coordinate covalent bond is present in the molecule. For drawing Lewis structure a systematic procedure is followed. They are,
- The total number of valence electrons that is present in molecule is calculated by adding all the valence electrons of the atoms present in the molecule.
- The chemical symbols for the atoms that is present in the molecule is written in the order that they are bonded. After this a single covalent bond is placed between each atoms as two electrons.
- The nonbonding electrons are added to each atom that is bonded to the central atom so that it contains octet of electrons. For hydrogen alone the “octet” is only two electrons.
- The remaining electrons has to be placed on the central atom in the structure.
- If there is no octet of electrons present in the central atom, then use one or more pairs of nonbonding electrons that is bonded to the central atom to form double or triple bonds.
- The total number of electrons has to be counted and it has to be confirmed whether the count is same as that of the number of valence electrons that is available for bonding.
(c)
Interpretation:
The total number of electron dots that is present in
Concept Introduction:
Lewis structure clearly depicts the bonding and nonbonding electrons in the atom. This is only partially useful for the molecule that contains one or more multiple bonds and when coordinate covalent bond is present in the molecule. For drawing Lewis structure a systematic procedure is followed. They are,
- The total number of valence electrons that is present in molecule is calculated by adding all the valence electrons of the atoms present in the molecule.
- The chemical symbols for the atoms that is present in the molecule is written in the order that they are bonded. After this a single covalent bond is placed between each atoms as two electrons.
- The nonbonding electrons are added to each atom that is bonded to the central atom so that it contains octet of electrons. For hydrogen alone the “octet” is only two electrons.
- The remaining electrons has to be placed on the central atom in the structure.
- If there is no octet of electrons present in the central atom, then use one or more pairs of nonbonding electrons that is bonded to the central atom to form double or triple bonds.
- The total number of electrons has to be counted and it has to be confirmed whether the count is same as that of the number of valence electrons that is available for bonding.
(b)
Interpretation:
The total number of electron dots that is present in
Concept Introduction:
Lewis structure clearly depicts the bonding and nonbonding electrons in the atom. This is only partially useful for the molecule that contains one or more multiple bonds and when coordinate covalent bond is present in the molecule. For drawing Lewis structure a systematic procedure is followed. They are,
- The total number of valence electrons that is present in molecule is calculated by adding all the valence electrons of the atoms present in the molecule.
- The chemical symbols for the atoms that is present in the molecule is written in the order that they are bonded. After this a single covalent bond is placed between each atoms as two electrons.
- The nonbonding electrons are added to each atom that is bonded to the central atom so that it contains octet of electrons. For hydrogen alone the “octet” is only two electrons.
- The remaining electrons has to be placed on the central atom in the structure.
- If there is no octet of electrons present in the central atom, then use one or more pairs of nonbonding electrons that is bonded to the central atom to form double or triple bonds.
- The total number of electrons has to be counted and it has to be confirmed whether the count is same as that of the number of valence electrons that is available for bonding.

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Chapter 5 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
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- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
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- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
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