The enthalpies of formation of elements such as P 4 ( s ) , H 2 ( g ) , or C ( graphite ) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

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Chapter 5, Problem 5.27QE

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Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

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Given: N2(g) + 3H2(g)2NH3(g) AG° = 53.8 kJ at 700K. Calculate AG for the above reaction at 700K if the reaction mixture consists of 20.0 atm of N2(g), 30.0 atm of H2(g), and 0.500 atm of NH3(g). A) -26.9 kJ B) 31.1 kJ C) -15.6 kJ D) 26.9 kJ E) -25.5 kJ

Explain the structure of the phosphomolybdate anion [PMo12O40]3-.

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Question

Chapter 5, Problem 5.27QE

Interpretation Introduction

Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

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Answer 3

Question

Chapter 5, Problem 5.27QE

Interpretation Introduction

Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

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Answer 4

Question

Chapter 5, Problem 5.27QE

Interpretation Introduction

Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

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Answer 5

Chapter 5, Problem 5.27QE

Interpretation Introduction

Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

Answer 6

Chapter 5, Problem 5.27QE

Interpretation Introduction

Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

Answer 7

Chapter 5, Problem 5.27QE

Interpretation Introduction

Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

Answer 8

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Answer 11

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The enthalpies of formation of elements such as P 4 ( s ) , H 2 ( g ) , or C ( graphite ) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

Solution Summary: The author explains that the enthalpies of formation of elements such as P_

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Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

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Chapter 5 Solutions

The enthalpies of formation of elements such as P 4 ( s ) , H 2 ( g ) , or C ( graphite ) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

Solution Summary: The author explains that the enthalpies of formation of elements such as P_

Videos

Interpretation: The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.

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Chapter 5 Solutions

Interpretation:

The enthalpies of formation of elements such as P4(s), H2(g), or C(graphite) are not necessary to involve in a standard enthalpies of formation; the reason has to be explained.