(a) Interpretation: The number of moles of nicotine smoked in a day is to be determined when it is considered that an individual smokes a pack of 20 cigarettes a day. The mass of the content of the cigarette is 1.93 mg and the molar mass is 162.3g/mol. Concept Introduction: The number of moles of a substance is obtained from the molar mass of the substance and given mass of the substance, using the following formula: n = m M Here, m is mass and M is molar mass.
(a) Interpretation: The number of moles of nicotine smoked in a day is to be determined when it is considered that an individual smokes a pack of 20 cigarettes a day. The mass of the content of the cigarette is 1.93 mg and the molar mass is 162.3g/mol. Concept Introduction: The number of moles of a substance is obtained from the molar mass of the substance and given mass of the substance, using the following formula: n = m M Here, m is mass and M is molar mass.
Solution Summary: The author explains that the number of moles of nicotine is determined when an individual smokes a pack of 20 cigarettes.
The number of moles of nicotine smoked in a day is to be determined when it is considered that an individual smokes a pack of 20 cigarettes a day. The mass of the content of the cigarette is 1.93 mg and the molar mass is 162.3g/mol.
Concept Introduction:
The number of moles of a substance is obtained from the molar mass of the substance and given mass of the substance, using the following formula:
n=mM
Here, m is mass and M is molar mass.
Interpretation Introduction
(b)
Interpretation:
The number of molecules of nicotine smoked in a day is to be determined when it is considered that an individual smokes a pack of 20 cigarettes a day. The mass of the content of the cigarette is 1.93mg and the molar mass is 162.3g/mol.
Concept Introduction:
The total number of molecules is determined by the multiplication of the total number of moles with the number of a molecule present in a mole.
This relation is given as-
Natoms/molecules=total number of moles×6.02×1023 atoms/molecules1mol
Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY