Chapter 5, Problem 3P

To determine

The speed of the ball.

Answer to Problem 3P

Solution:

  $\text{11}\text{.81}{\text{m/s}}^{\text{2}}$

Explanation of Solution

Given:

  $\begin{array}{l}{F}_{net}=310\text{N}\\ m=2.0\text{kg}\\ r=0.90\text{m}\end{array}$

Formula used:

The relation between net forces on a body moves in a circle, speed and radius of the circular path. $F=\frac{m{v}^2}{r}$

F : net force on a body in uniform circular motion

v : speed of the particle

r : radius of the circular path.

Calculation:

  $\begin{array}{l}F=\frac{m{v}^2}{r}\\ v=\sqrt{\frac{F.r}{m}}\\ v=\sqrt{\frac{310\times 0.90}{2.0}}\\ v=11.81{\text{m/s}}^{\text{2}}\end{array}$

Conclusion:Speed of particle moving in the circular path $\text{=11}\text{.81}{\text{m/s}}^{\text{2}}$ .