Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 5, Problem 78GP

(a)

To determine

To find: That why stars don’t crashes.

(a)

Expert Solution
Check Mark

Explanation of Solution

Introduction:

The force of mutual gravity is providing the centripetal force.

The mutual attractions of stars are providing the necessary centripetal force for rotation. That’s why they don’t crashes with each other.

When two stars rotate in a circular motion, the gravitational force between the two stars is measured by

attraction between the two stars. So the stars will not hit each other.

Conclusion:

Therefore we conclude that as they are revolving with calculated speed so they don’t crash.

(b)

To determine

To find: The mass of each star.

(b)

Expert Solution
Check Mark

Answer to Problem 78GP

  9.6×1026 kg

Explanation of Solution

Given Data:

  D=8×1010 m

  T=12.6 year

Formula Used:

Gravitational force between stars each of mass m is given by

  F=Gmmr2

Speed v of star related to period of revolution T,

  v=2π(r/2)T=πrT

Centripetal force acts on each star,

  Fc=mv2(r/2)

Putting value of v in above equation

  Fc=m(πrT)2(r/2)=2mπ2rT2

The centripetal force acting on the star is balanced by gravitational force between two stars

  F=FcGmmr2=2mπ2rT2m=2π2r3GT2

Calculation:

Substituting the given values

  m=2π2r3GT2=2π2×(8.0×1010m)3(6.67×1011Nm2/kg2)[((12.6y)(365.5 days 1.0 year )(24h1.0 day )(60min1.0h)(60s1.0min)]2=9.6×1026 kg

Conclusion:

Therefore, the mass of stars are 9.6×1026 kg .

Chapter 5 Solutions

Physics: Principles with Applications

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