Chapter 5, Problem 68GP

To determine

The pulling force on one another.

Answer to Problem 68GP

The pulling force on one another is $303.2\text{N}$ .

Explanation of Solution

Given info:

The time for one spin of circle is, $T=2.5\text{s}$

The length of the arms is, $l=0.80\text{m}$ .

The mass of each skater is, $m=60\text{kg}$ .

Formula Used:

The expression to calculate the pulling force on one another is,

  $F=\frac{4{\pi }^{2}ml}{T^2}$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}F=\frac{4{\pi }^2\left(60\text{kg}\right)\left(0.80\text{m}\right)}{{\left(2.5\text{s}\right)}^2}\\ =303.2\text{N}\end{array}$

Conclusion:

Thus, the pulling force on one another is $303.2\text{N}$ .