Chapter 5, Problem 33P

To determine

The acceleration due to gravity on the moon.

Answer to Problem 33P

Solution:

The acceleration due to gravity on the moon is $1.62{\text{m/s}}^{\text{2}}$ .

Explanation of Solution

Given:

The radius of moon $r=1.74\times {10}^6\text{m}$

Mass of moon $m=7.35\times {10}^{\text{22}}\text{kg}$

Formula Used:

Acceleration due to gravity on the surface is given by:

  $g=\frac{Gm}{r^2}$

Where, m is the mass of the body and r is its radius.

Calculation:

Substitute the values:

  $\begin{array}{l}g=\frac{6.67\times {10}^{{}^{-11}}(7.35\times {10}^{22})}{{\left(1.7\times {10}^6\right)}^2}\\ g=1.62{\text{m/s}}^{\text{2}}\end{array}$

Conclusion:

Hence, the acceleration due to gravity on the moon is $1.62{\text{m/s}}^{\text{2}}$ .