Chapter 5, Problem 26CR

Interpretation Introduction

(a)

Interpretation:

Interpret formula of Copper(i) iodide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is CuI.

Explanation of Solution

Copper(i) is denoted as Cu+ while iodide denoted as I- and thus formula of given compound is CuI.

Interpretation Introduction

(b)

Interpretation:

Interpret formula of Cobaltous chloride.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is CoCl₂.

Explanation of Solution

Cobalt is present in lower oxidation state such as + 2 and thus formula of given compound is CoCl₂.

Interpretation Introduction

(c)

Interpretation:

Interpret formula of Silver sulfide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is AgF.

Explanation of Solution

Ag is present in lower oxidation state such as + 1 and thus formula of given compound is AgF.

Interpretation Introduction

(d)

Interpretation:

Interpret formula of Mercurous bromide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is HgBr₂.

Explanation of Solution

Hg is present in lower oxidation state such as + 2 and thus formula of given compound is HgBr₂.

Interpretation Introduction

(e)

Interpretation:

Interpret formula of Mercuric oxide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is Hg₂ O₃.

Explanation of Solution

Hg is present in higher oxidation state such as + 3 and thus formula of given compound is Hg₂ O₃.

Interpretation Introduction

(f)

Interpretation:

Interpret formula of Chromium (iii) sulfide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is Cr₂ S₃.

Explanation of Solution

Cr is present in higher oxidation state such as + 3 and thus formula of given compound is Cr₂ S₃.

Interpretation Introduction

(g)

Interpretation:

Interpret formula of Plumbic oxide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is PbO₂.

Explanation of Solution

Pb is present in higher oxidation state such as + 4 and thus formula of given compound is PbO₂.

Interpretation Introduction

(h)

Interpretation:

Interpret formula of Potassium nitride.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is K₃ N.

Explanation of Solution

N is present in oxidation state such as -3 and thus formula of given compound is K₃ N.

Interpretation Introduction

(i)

Interpretation:

Interpret formula of Stannous fluoride.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is SnF₂.

Explanation of Solution

Sn² + is present in lower oxidation state such as + 2 and thus formula of given compound is SnF₂.

Interpretation Introduction

(j)

Interpretation:

Interpret formula of Ferric oxide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR

The formula of given compound is Fe₂ O₃.

Explanation of Solution

Fe is present in higher oxidation state such as + 3 and thus formula of given compound is Fe₂ O₃.