(a)
Interpretation:
Interpret formula of Copper(i) iodide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is CuI.
Explanation of Solution
Copper(i) is denoted as Cu+ while iodide denoted as I- and thus formula of given compound is CuI.
(b)
Interpretation:
Interpret formula of Cobaltous chloride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is CoCl2.
Explanation of Solution
Cobalt is present in lower oxidation state such as + 2 and thus formula of given compound is CoCl2.
(c)
Interpretation:
Interpret formula of Silver sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is AgF.
Explanation of Solution
Ag is present in lower oxidation state such as + 1 and thus formula of given compound is AgF.
(d)
Interpretation:
Interpret formula of Mercurous bromide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is HgBr2.
Explanation of Solution
Hg is present in lower oxidation state such as + 2 and thus formula of given compound is HgBr2.
(e)
Interpretation:
Interpret formula of Mercuric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Hg2 O3.
Explanation of Solution
Hg is present in higher oxidation state such as + 3 and thus formula of given compound is Hg2 O3.
(f)
Interpretation:
Interpret formula of Chromium (iii) sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Cr2 S3.
Explanation of Solution
Cr is present in higher oxidation state such as + 3 and thus formula of given compound is Cr2 S3.
(g)
Interpretation:
Interpret formula of Plumbic oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is PbO2.
Explanation of Solution
Pb is present in higher oxidation state such as + 4 and thus formula of given compound is PbO2.
(h)
Interpretation:
Interpret formula of Potassium nitride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is K3 N.
Explanation of Solution
N is present in oxidation state such as -3 and thus formula of given compound is K3 N.
(i)
Interpretation:
Interpret formula of Stannous fluoride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is SnF2.
Explanation of Solution
Sn2 + is present in lower oxidation state such as + 2 and thus formula of given compound is SnF2.
(j)
Interpretation:
Interpret formula of Ferric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Fe2 O3.
Explanation of Solution
Fe is present in higher oxidation state such as + 3 and thus formula of given compound is Fe2 O3.
Want to see more full solutions like this?
Chapter 5 Solutions
Introductory Chemistry: A Foundation
- Question 2 show work. don't Compound give Ai generated solution So (J K-1 mol-1) A 26 B 54 C 39 D 49 At 298 K, AG° is 375 kJ for the reaction 1A + 1B → 4C + 2D Calculate AH° for this reaction in kJ.arrow_forward1. Provide a complete IUPAC name for each of the following compounds. a) b) c) OH OH OH a) b) c) 2. Provide a complete IUPAC name for each of the following compounds. a) b) a) OH b) он c) OB >=arrow_forwardc) 3. Provide a common name for each of the following alcohols. a) a) OH b) OH c) HO b) c) 4. Provide a common name for each of the following compounds. b) OH a) 5 a) Y OH c) OHarrow_forward
- Using the critical constants for water (refer to the table in the lecture slides), calculate the second virial coefficient. Assume that the compression factor (Z) is expressed as an expansion series in terms of pressure.arrow_forward+3413 pts /4800 Question 38 of 48 > Write the full electron configuration for a Kion. © Macmillan Learning electron configuration: ↓ Resources Solution Penalized → Al Tutor Write the full electron configuration for an Fion. electron configuration: T G 6 & 7 Y H כ Y 00 8 hp 9 J K no L 144 P 112 | t KC 47°F Clear ins prt sc delete ] backspace erarrow_forwardHow to solve these types of problems step by step? I'm so confused.arrow_forward
- Identify the expected product of the following Claisen rearrangement. || = IV OV 00000 5 ОН Он Он Он Он || III IV Varrow_forwardCan you please color-code and explain how to solve this and any molecular orbital diagram given? I'm so confused; could you provide baby steps regardless of which problem type they gave me?arrow_forwardConsider the following structure. OH Esmolol The synthesis of this compound uses a building block derived from either ethylene oxide or epichlorohydrin. 1) Determine which building block was used: | 2) Draw the structure of the nucleophiles that were used along with this building block in the synthesis of the molecule. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. You do not have to consider stereochemistry. Θε {n [arrow_forward
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning