(a)
Interpretation:
Interpret name of ionic substance with charge specifying by roman number for SnCl2.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
(b)
Interpretation:
Interpret name of ionic substance with charge specifying by roman number for Fe2 S3.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
Trending nowThis is a popular solution!
Chapter 5 Solutions
Introductory Chemistry: A Foundation
- For the following processes that show the formation of ions, use the periodic table to indicate the number of electrons and protons present in both theionand theneutral atomfrom which the ion is made. a.CaCa2++2e b.P+3eP3 c.Br+eBr d.FeEe3++3e e.AlAl3++3e f.N+3eN3arrow_forwardThe isotope of an unknown element, X, has a mass number of 79. The most stable ion of the isotope has 36 electrons and forms a binary compound with sodium, having a formula of Na2X. Which of the following statements is(are) true? For the false statements, correct them. a. The binary compound formed between X and fluorine will be a covalent compound. b. The isotope of X contains 38 protons. c. The isotope of X contains 41 neutrons. d. The identity of X is strontium, Sr.arrow_forwardComplete the table by placing symbols, formulas, and names in the blanks.arrow_forward
- Name the compounds in parts a-d and write the formulas for the compounds in parts eh. a. Hg2O b. FeBr3 c. CoS d. TiCl4 e. tin(II) nitride f. cobalt(III) iodide g. mercury(II) oxide h. chromium(VI) sulfidearrow_forwardName the compounds in parts ad and write the formulas for the compounds in parts eh. a. NaBr b. Rb2O c. CaS d. AlI3 e. strontium fluoride f. aluminum selenide g. potassium nitride h. magnesium phosphidearrow_forwardWrite the formula for each of the following compounds: a. ammonium hydrogen phosphate b. mercury (I) sulfide c. silicon dioxide d. sodium sulfite e. aluminum hydrogen sulfate f. nitrogen trichloride g. hydiobromic acid h. bromous acid i. perbromic acid j. potassium hydrogen sulfide k. calcium iodide l. cesium perchloratearrow_forward
- Each of the following compounds is incorrectly named is wrong with each name, and what is the correct name each compound? a. FeCl3 iron chloride b. NO2, nitrogen(IV) oxide c. CaO, calcium(II) monoxide d. Al2S3, dialuminum trisulfide e. Mg(C2,H3O2)2, manganese diacetate f. FePO4, iron(II) phosphide g. P2S5, phosphorus sulfide h. Na2O2, sodium oxide i. HNO3 nitrate acid j. H2S, sulfuric acidarrow_forwardThe formula of water is If-O. Which of the following is indicated by this formula? Explain your answer. a. The mass of hydrogen is twice that of oxygen in each molecule. b. There are two hydrogen atoms and one oxygen atom per water molecule. c. The mass of oxygen is twice that of hydrogen in each molecule. d. There are two oxygen atoms and one hydrogen atom per water molecule.arrow_forwardWhich of the following is true about an individual atom? Explain. a. An individual atom should be considered to be a solid. b.An individual atom should be considered to be a liquid. c. An individual atom should be considered to be a gas. d. The state of the atom depends on which element it is. e. An individual atom cannot be considered to be a solid, liquid, or gas. Justify your choice, and for choices you did not pick, explain what is wrong with them.arrow_forward
- For each of the following ions, indicate the number of protons and electrons the ion contains. a. Ba2+ b. Zn2+ c. N3 d. Rb e. Co3 f. Te2 g. Brarrow_forwardEach of the following statements is true, but Dalton might have had trouble explaining some of them with his atomic theory. Give explanations for the following statements. a. The space-filling models for ethyl alcohol and dimethyl ether are shown below. These two compounds have die same composition by mass (52% carbon, 13% hydrogen, and 35% oxygen), yet the two have different melting points, boiling points, and solubilities in water. b. Burning wood leaves an ash that is only a small fraction of the mass of the original wood. c. Atoms can be broken down into smaller particles. d. One sample of lithium hydride is 87.4% lithium by mass, while another sample of lithium hydride Ls 74.9% lithium by mass. However, the two samples have the same chemical properties.arrow_forwardThe element europium exists in nature as two isotopes: 151Eu has a mass of 150.9196 amu, and 153Eu has a mass of 152.9209 amu. The average atomic mass of europium is 151.96 amu. a. Calculate the relative abundance of the two europium isotopes. b. Graph each fractional abundance value as a y-axis value in association with its corresponding mass value on the x-axis. Starting from each x-axis value, where y = 0, draw a vertical line up to the fractional abundance value. The result will approximate the type of visual graph a mass spectrometer would yield for europium in the 150155 amu range.arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning