Database Systems: Design, Implementation & Management
13th Edition
ISBN: 9781337670562
Author: Coronel
Publisher: Cengage
expand_more
expand_more
format_list_bulleted
Concept explainers
Expert Solution & Answer
Chapter 5, Problem 1RQ
Explanation of Solution
Entity Supertype:
- The entity supertype is an entity type that has the relation with one or more subtypes and it contains the common attributes of its subtypes.
- The entity subtype is a grouping of entities type in single entity that shares the common attributes or relationships which are different from other grouping.
Use of entity supertype:
The reason for using entity supertype is to reduce redundant relationships and also reduce the number of nulls.
Example:
The following example demonstrates the “supertype” entity, “subtype” entity, and “discriminator”.
Explanation:
- Here, “Employee” entity is a “supertype” entity.
- “Hourly Employee”, “Salaried Employee”, and “Consultant” are the “Sub type” entities.
- “Emp_type” is a discriminator to select appropriate “subtype”.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
I would like to know the main features about the following three concepts:
1. Default forwarded
2. WINS Server
3. IP Security (IPSec).
Chapter 5 Solutions
Database Systems: Design, Implementation & Management
Ch. 5 - Prob. 1RQCh. 5 - What kinds of data would you store in an entity...Ch. 5 - Prob. 3RQCh. 5 - What is a subtype discriminator? Give an example...Ch. 5 - Prob. 5RQCh. 5 - What is a disjoint subtype? Give an example.Ch. 5 - What is the difference between partial...Ch. 5 - Prob. 8RQCh. 5 - According to the data model, is it required that...Ch. 5 - Prob. 10RQ
Ch. 5 - Prob. 11RQCh. 5 - Prob. 12RQCh. 5 - Prob. 13RQCh. 5 - Prob. 14RQCh. 5 - When implementing a 1:1 relationship, where should...Ch. 5 - What is time-variant data, and how would you deal...Ch. 5 - Prob. 17RQCh. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8CCh. 5 - Prob. 9CCh. 5 - Prob. 10C
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Similar questions
- map the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation. NOTE: Need relational database schema diagramarrow_forwardWhat is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forward
- Task 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forwardCan you please solve this without AIarrow_forward1. Create a Vehicle.java file. Implement the public Vehicle and Car classes in Vehicle.java, including all the variables and methods in the UMLS. Vehicle - make: String model: String -year: int + Vehicle(String make, String, model, int, year) + getMake(): String + setMake(String make): void + getModel(): String + setModel(String model): void + getYear(): int + set Year(int year): void +toString(): String Car - numDoors: int + numberOfCar: int + Car(String make, String, model, int, year, int numDoors) + getNumDoors(): int + setNumDoors (int num Doors): void + toString(): String 2. Create a CarTest.java file. Implement a public CarTest class with a main method. In the main method, create one Car object and print the object using System.out.println(). Then, print the numberOfCar. Your printing result must follow the example output: make Toyota, model=Camry, year=2022 numDoors=4 1 Hint: You need to modify the toString methods in the Car class and Vehicle class!arrow_forward
- CHATGPT GAVE ME WRONG ANSWER PLEASE HELParrow_forwardHELP CHAT GPT GAVE ME WRONG ANSWER Consider the following implementation of a container that will be used in a concurrent environment. The container is supposed to be used like an indexed array, but provide thread-safe access to elements. struct concurrent_container { // Assume it’s called for any new instance soon before it’s ever used void concurrent_container() { init_mutex(&lock); } ~concurrent_container() { destroy_mutex(&lock); } // Returns element by its index. int get(int index) { lock.acquire(); if (index < 0 || index >= size) { return -1; } int result = data[index]; lock.release(); return result; } // Sets element by its index. void set(int index, int value) { lock.acquire(); if (index < 0 || index >= size) { resize(size); } data[index] = value; lock.release(); } // Extend maximum capacity of the…arrow_forwardWrite a C program using embedded assembler in which you use your own function to multiply by two without using the product. Tip: Just remember that multiplying by two in binary means shifting the number one place to the left. You can use the sample program from the previous exercise as a basis, which increments a variable. Just replace the INC instruction with SHL.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Database Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781285196145Author:Steven, Steven Morris, Carlos Coronel, Carlos, Coronel, Carlos; Morris, Carlos Coronel and Steven Morris, Carlos Coronel; Steven Morris, Steven Morris; Carlos CoronelPublisher:Cengage Learning
Database Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781305627482Author:Carlos Coronel, Steven MorrisPublisher:Cengage Learning
Principles of Information Systems (MindTap Course...Computer ScienceISBN:9781285867168Author:Ralph Stair, George ReynoldsPublisher:Cengage Learning
Fundamentals of Information SystemsComputer ScienceISBN:9781305082168Author:Ralph Stair, George ReynoldsPublisher:Cengage Learning
A Guide to SQLComputer ScienceISBN:9781111527273Author:Philip J. PrattPublisher:Course Technology Ptr
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781285196145
Author:Steven, Steven Morris, Carlos Coronel, Carlos, Coronel, Carlos; Morris, Carlos Coronel and Steven Morris, Carlos Coronel; Steven Morris, Steven Morris; Carlos Coronel
Publisher:Cengage Learning
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781305627482
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning
Principles of Information Systems (MindTap Course...
Computer Science
ISBN:9781285867168
Author:Ralph Stair, George Reynolds
Publisher:Cengage Learning
Fundamentals of Information Systems
Computer Science
ISBN:9781305082168
Author:Ralph Stair, George Reynolds
Publisher:Cengage Learning
A Guide to SQL
Computer Science
ISBN:9781111527273
Author:Philip J. Pratt
Publisher:Course Technology Ptr