Explanation Given information: The allowable normal stress of the material is σ a l l = 22 ksi . Design of beam: Show the free-body diagram of the beam as in Figure 1. Determine the vertical reaction at point E by taking moment at point A . ∑ M A = 0 − 8 ( 4.5 ) − 32 ( 18.5 ) − 32 ( 32.5 ) + E y ( 42 ) = 0 − 36 − 592 − 1040 + 42 E y = 0 E y = 39.7143 kips Determine the vertical reaction at point A by resolving the vertical component of forces. ∑ F y = 0 A y − 8 − 32 − 32 + E y = 0 A y − 72 + 39.7143 = 0 A y = 32.2857 kips Shear force: Show the calculation of shear force as follows; V A = 32.2857 kips V B − V A = 0 V B L e f t = V A = 32.2857 kips V B R i g h t = 32.2857 − 8 = 24.2857 kips V C − V B = 0 V C L e f t = V B = 24.2857 kips V R R i g h t = 24.2857 − 32 = − 7.7143 kips V D − V C = 0 V D L e f t = V C = − 7.7143 kips V D R i g h t = V C = − 7.7143 − 32 = − 39.7143 kips V E − V D = 0 V E L e f t = V D = − 39.7143 kips Show the calculated shear force values as in Table 1. Location ( x ) ft Shear force ( V ) kips A 32.2857 B (Left) 32.2857 B (Right) 24.2857 C (Left) 24.2857 C (Right) –7.7143 D (Left) –7.7143 D (Right) –39.7143 E –39.7143 Plot the shear force diagram as in Figure 2. Bending moment: Show the calculation of the bending moment as follows; M A = 0 M B − M A = 32.2857 × 4.5 M B = 145.286 + M A = 145.286 + 0 = 145.286 kips-ft M C − M B = 24.2857 × 14 M C = 340 + M B = 340 + 145.286 = 485.286 kips-ft M D − M C = − 7.7143 × 14 M D = − 108 + M C = − 108 + 485

7th Edition

ISBN: 9780073398235

Author: Ferdinand P. Beer, E. Russell Johnston Jr., John T. DeWolf, David F. Mazurek

Publisher: McGraw-Hill Education

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Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial…

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Chapter 5, Problem 160RP

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The minimum flange width b.

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Chapter 5, Problem 159RP

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Ch. 5.1 - 5.1 through 5.6 For the beam and loading shown,...Ch. 5.1 - 5.1 through 5.6 For the beam and loading shown,...Ch. 5.1 - 5.1 through 5.6 For the beam and loading shown,...Ch. 5.1 - 5.1 through 5.6 For the beam and loading shown,...Ch. 5.1 - 5.1 through 5.6 For the beam and loading shown,...Ch. 5.1 - 5.1 through 5.6 For the beam and loading shown,...Ch. 5.1 - 5.7 and 5.8 Draw the shear and bending-moment...Ch. 5.1 - 5.7 and 5.8 Draw the shear and bending-moment...Ch. 5.1 - 5.9 and 5.10 Draw the shear and bending-moment...Ch. 5.1 - 5.9 and 5.10 Draw the shear and bending-moment...

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The minimum flange width b .

Solution Summary: The author shows the free-body diagram of the beam as in Figure 1. Determine the vertical reaction at point E by resolving vertical component of forces.

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