By analyzing the diagram, it should be explained the pressure change in the container A Concept introduction: Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber. The rate of effusion is the measure speed at which the gas is transferred to the chamber According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is, Graham’s law of effusion, R a t e o f e f f u s i o n f o r g a s 1 R a t e o f e f f u s i o n f o r g a s 2 = M 2 M 1 o r R a t e 1 R a t e 2 = ( M 2 M 1 ) 1 / 2 M 1 and M 2 are the molar masses of twogases

Question

Examine the reaction below. Highlight all bonds that have broken in the reactant. Br H H₂C-C- -H 5 H-C-H H-C-H BIE 们 OH H H H₂C-C= H-C-H H-C-H

Answer 1

Question

Chapter 5, Problem 148AE

Interpretation Introduction

Interpretation:

By analyzing the diagram, it should be explained the pressure change in the container A

Concept introduction:

Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber.

The rate of effusion is the measure speed at which the gas is transferred to the chamber

According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles.

The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is,

Graham’s law of effusion,

Rate of effusion for gas 1Rate of effusion for gas 2 =M2M1 orRate1Rate2 = (M2M1)1/2

M1 and M2 are the molar masses of twogases

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