From the relative rates of effusion of two gases, the effusion time for a particular gas should be determined Concept introduction: Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber. The rate of effusion is the measure of speed at which the gas is transferred to the chamber. According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is, R a t e o f e f f u s i o n f o r g a s 1 R a t e o f e f f u s i o n f o r g a s 2 = M 2 M 1 o r R a t e 1 R a t e 2 = ( M 2 M 1 ) 1 / 2 M 1 and M 2 are the molar masses of gas 1 and gas 2 This equation is known as Graham’s law of effusion. Effusion rate in some cases, equal to the volume of gas that effuses per unit volume.
From the relative rates of effusion of two gases, the effusion time for a particular gas should be determined Concept introduction: Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber. The rate of effusion is the measure of speed at which the gas is transferred to the chamber. According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is, R a t e o f e f f u s i o n f o r g a s 1 R a t e o f e f f u s i o n f o r g a s 2 = M 2 M 1 o r R a t e 1 R a t e 2 = ( M 2 M 1 ) 1 / 2 M 1 and M 2 are the molar masses of gas 1 and gas 2 This equation is known as Graham’s law of effusion. Effusion rate in some cases, equal to the volume of gas that effuses per unit volume.
Solution Summary: The author explains how the effusion rate of a gas is inversely proportional to the square root of the masses of its particles.
Interpretation: From the relative rates of effusion of two gases, the effusion time for a particular gas should be determined
Concept introduction:
Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber.
The rate of effusion is the measure of speed at which the gas is transferred to the chamber.
According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles.
The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is,
81. a. Propose a mechanism for the following reaction:
OH
CH2=CHCHC=N
b. What is the product of the following reaction?
HO
H₂O
N=CCH2CH2CH
OH
HO
CH3CCH=CH2
H₂O
C=N
82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium ulia
For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check
the appropriate box.
Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below.
Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions
- just focus on the first stable product you expect to form in solution.
?
NH2
MgBr
Will the first product that forms in this reaction
create a new CC bond?
○ Yes
○ No
MgBr
?
Will the first product that forms in this reaction
create a new CC bond?
O Yes
O No
Click and drag to start drawing a
structure.
:☐
G
x
c
olo
Ar
HE
Predicting
As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule
with a new C - C bond as its major product:
H₂N
O
H
1.
?
2. H3O+
If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more
than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for
example to distinguish between major products with different stereochemistry.
0
If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank.
فا
Explanation
Check
Click and drag to start drawing a
structure.
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