Chapter 4.6, Problem 34SR

To determine

The equation of the straight line $y+3=-\frac{1}{4}\left(x+2\right)$ in standard form of a line.

Answer to Problem 34SR

The equation of straight line in standard form is $x+4y=-14$ .

Explanation of Solution

Given: The given equation of the straight line is $y+3=-\frac{1}{4}\left(x+2\right)$ .

Formula used: The equation of the straight line in standard form is of the form $ax+by=c$ .

Calculation: The given equation of the line is $y+3=-\frac{1}{4}\left(x+2\right)$ . Now, converting the given equation of line in standard form as

  $\begin{array}{c}y+3=-\frac{1}{4}\left(x+2\right)\\ 4y+12=-x-\mathrm{2......}\left(\text{Cross-multiplying}\right)\\ \text{or, }x+4y=-14\end{array}$