Chapter 4, Problem 20MCQ

To determine

To write:The given equation in slope intercept form.

Answer to Problem 20MCQ

The slope intercept form of the given equation is $y=\frac{1}{2}x-5$ .

Explanation of Solution

Given:

The equation is $y+1=\frac{1}{2}\left(x-8\right)$

Calculation:

The standard form of slope and point form of the straight line is $y-y_1=m\left(x-x_1\right)$ .

Here m is the slope of the straight line and $\left(x_1,y_1\right)$ is the point from which the straight line passes.

Converting the given equation in the standard form:

  $\begin{array}{l}y+1=\frac{1}{2}\left(x-8\right)\\ y+1=\frac{1}{2}x-4\\ y=\frac{1}{2}x-5\end{array}$

From the slope intercept form of the equation, following information can be obtained.

The slope m of the equation is $\frac{1}{2}$ and the intercept of the line on y -axis is $-5$ .

Therefore, the standard form of the slope and intercept form of the equation of the straight line is $y=\frac{1}{2}x-5$ .