Concept explainers
(a)
Toplot:The graph representing temperature drop from 0 to 8 minutes.
(a)
Answer to Problem 58PPS
The graph of the given situation is drawn below.
Explanation of Solution
Given:
The initial temperature
The rate of temperature drop =
Calculation:
The standard form of slope and intercept form of the straight line is
Here m is the slope of the straight line and c is the y- intercept of the equation.
The initial temperature is the intercept of the line on the y- axis while the rate of temperature drop is the slope of the equation.
To plot the graph, write the equation for the given situation.
Substitute -3 for slope m and 80 for y- intercept c .
The equation of the straight line in the slope and intercept form is
Here, t is the temperature in minutes. The negative sign shows the drop in temperature with time.
Therefore, the equation of the straight line is
The temperature at time t = 0 minutes is
The temperature at time t = 8 minutes is
(b)
Tofind:The equation for temperature drop overnight.
(b)
Answer to Problem 58PPS
The equation for temperature drop overnight is
Explanation of Solution
Given:
The initial temperature
The rate of temperature drop =
Calculation:
The standard form of slope and intercept form of the straight line is
Here m is the slope of the straight line and c is the y- intercept of the equation.
The initial temperature is the intercept of the line on the y- axis while the rate of temperature drop is the slope of the equation.
To plot the graph, write the equation for the given situation.
Substitute -3 for slope m and 80 for y- intercept c .
The equation of the straight line in the slope and intercept form is
Here, the variablet is the temperature in minutes. The negative sign shows the drop in temperature with time. The constant 80 represents the temperature which does not vary with time.
Therefore, the equation of the straight line is
Chapter 4 Solutions
Algebra 1
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