Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 45, Problem 69AP
(a)
To determine
The required amount of cooling water.
(b)
To determine
The magnitude of rate of fuel burning.
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1. Suppose a woman does 500 J of work and -9400 J of heat transfer occurs into the environment in
the process.
(a) What is the decrease in her internal energy, assuming no change in temperature or consumption
of food? (That is, there is no other energy transfer.)
ΔΕint
✓ J
(b) The internal energy is stored energy due to food intake. Treating the change in internal energy as
the input energy and work done as output, what is her efficiency?
Efficiency, Eff:
%
(c) What physics law did you use in this problem?
Zeroth Law of Thermodynamics
First Law of Thermodynamics
Second Law of Thermodynamics
By jogging, a girl is converting food energy into internal energy at the rate of 399 kcal/h above her basal metabolic rate (BMR). Some of this additional internal energy immediately goes into work done at a rate of 56.1 W. The rest of this additional energy would go into raising her temperature, but it is
instead eliminated by evaporation of perspiration to keep her body temperature constant. Assume that the heat of evaporation of water at body temperature is equal to its heat of vaporization at 100°C.
(a) Determine the hourly rate (in kg/h) at which water must evaporate from her skin.
kg/h
(b) When fat is metabolized, hydrogen atoms in fat molecules are transferred to oxygen to form water. Assume that the metabolism of 1.00 g of fat generates 9.00 kcal of energy and produces 1.00 g of water. What percent of the water needed is generated by burning fat?
A liquid food product (P) is being cooled from 80°C to 30°C in an indirect heat exchanger using cold water (W) as a cooling medium. If the product mass flow rate is 1800 kg/h, determine the water flow rate required to accomplish product cooling if the water is allowed to increase its temperature from 10°C to 20°C in the heat exchanger. The specific heat of the product is 3.8 kJ/kg K, and the value for water is 4.1kJ/kg K.
Chapter 45 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 45.1 - When a nucleus undergoes fission, the two daughter...Ch. 45.2 - Prob. 45.2QQCh. 45.3 - Prob. 45.3QQCh. 45.4 - Prob. 45.4QQCh. 45 - Prob. 1OQCh. 45 - Prob. 2OQCh. 45 - Prob. 3OQCh. 45 - Prob. 4OQCh. 45 - Prob. 5OQCh. 45 - Prob. 6OQ
Ch. 45 - Prob. 7OQCh. 45 - Prob. 8OQCh. 45 - Prob. 9OQCh. 45 - Prob. 1CQCh. 45 - Prob. 2CQCh. 45 - Prob. 3CQCh. 45 - Prob. 4CQCh. 45 - Prob. 5CQCh. 45 - Prob. 6CQCh. 45 - Prob. 7CQCh. 45 - Prob. 8CQCh. 45 - Prob. 1PCh. 45 - Prob. 2PCh. 45 - Prob. 3PCh. 45 - Prob. 4PCh. 45 - Prob. 5PCh. 45 - Prob. 6PCh. 45 - Prob. 7PCh. 45 - Prob. 8PCh. 45 - Prob. 9PCh. 45 - Prob. 10PCh. 45 - Prob. 11PCh. 45 - Prob. 12PCh. 45 - Prob. 13PCh. 45 - Prob. 14PCh. 45 - Prob. 15PCh. 45 - Prob. 16PCh. 45 - Prob. 18PCh. 45 - Prob. 19PCh. 45 - Prob. 20PCh. 45 - Prob. 21PCh. 45 - Prob. 22PCh. 45 - Prob. 23PCh. 45 - Prob. 24PCh. 45 - Prob. 25PCh. 45 - Prob. 26PCh. 45 - Prob. 27PCh. 45 - Prob. 28PCh. 45 - Prob. 29PCh. 45 - Prob. 30PCh. 45 - Prob. 31PCh. 45 - Prob. 32PCh. 45 - Prob. 33PCh. 45 - Prob. 34PCh. 45 - Prob. 35PCh. 45 - Prob. 36PCh. 45 - Prob. 37PCh. 45 - Prob. 41PCh. 45 - Prob. 42PCh. 45 - Prob. 43PCh. 45 - Prob. 44PCh. 45 - Prob. 45PCh. 45 - Prob. 46APCh. 45 - Prob. 47APCh. 45 - Prob. 48APCh. 45 - Prob. 49APCh. 45 - Prob. 51APCh. 45 - Prob. 52APCh. 45 - Prob. 53APCh. 45 - Prob. 54APCh. 45 - Prob. 55APCh. 45 - Prob. 56APCh. 45 - Prob. 57APCh. 45 - Prob. 58APCh. 45 - Prob. 59APCh. 45 - Prob. 60APCh. 45 - Prob. 61APCh. 45 - Prob. 62APCh. 45 - Prob. 63APCh. 45 - Prob. 64APCh. 45 - Prob. 65APCh. 45 - Prob. 66APCh. 45 - Prob. 67APCh. 45 - Prob. 68APCh. 45 - Prob. 69APCh. 45 - Prob. 70APCh. 45 - Prob. 71APCh. 45 - Prob. 72APCh. 45 - Prob. 73AP
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