Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 45, Problem 33P
(a)
To determine
The half thickness for the material.
(b)
To determine
The thickness changes of the material by a factor of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The linear absorption coefficient for 1-MeV gamma rays in lead is 78 m1. Find the thickness of lead required to reduce by one-fourth the intensity of beam of such gamma rays.
The linear attenuation coefficient for 2.0-MeV gamma rays in water is 4.9 m-1 and 52 m-1 in lead. What thickness of water would give the same shielding for gamma rays as 15 mm of lead?
A 70-kg researcher absorbs 4.5 × neutrons in a work day, each of energy 1.2 MeV. The relative biological effectiveness (RBE) for these neutrons is 10. What is the equivalent dosage of the radiation exposure for this researcher, in millirem?
Chapter 45 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 45.1 - When a nucleus undergoes fission, the two daughter...Ch. 45.2 - Prob. 45.2QQCh. 45.3 - Prob. 45.3QQCh. 45.4 - Prob. 45.4QQCh. 45 - Prob. 1OQCh. 45 - Prob. 2OQCh. 45 - Prob. 3OQCh. 45 - Prob. 4OQCh. 45 - Prob. 5OQCh. 45 - Prob. 6OQ
Ch. 45 - Prob. 7OQCh. 45 - Prob. 8OQCh. 45 - Prob. 9OQCh. 45 - Prob. 1CQCh. 45 - Prob. 2CQCh. 45 - Prob. 3CQCh. 45 - Prob. 4CQCh. 45 - Prob. 5CQCh. 45 - Prob. 6CQCh. 45 - Prob. 7CQCh. 45 - Prob. 8CQCh. 45 - Prob. 1PCh. 45 - Prob. 2PCh. 45 - Prob. 3PCh. 45 - Prob. 4PCh. 45 - Prob. 5PCh. 45 - Prob. 6PCh. 45 - Prob. 7PCh. 45 - Prob. 8PCh. 45 - Prob. 9PCh. 45 - Prob. 10PCh. 45 - Prob. 11PCh. 45 - Prob. 12PCh. 45 - Prob. 13PCh. 45 - Prob. 14PCh. 45 - Prob. 15PCh. 45 - Prob. 16PCh. 45 - Prob. 18PCh. 45 - Prob. 19PCh. 45 - Prob. 20PCh. 45 - Prob. 21PCh. 45 - Prob. 22PCh. 45 - Prob. 23PCh. 45 - Prob. 24PCh. 45 - Prob. 25PCh. 45 - Prob. 26PCh. 45 - Prob. 27PCh. 45 - Prob. 28PCh. 45 - Prob. 29PCh. 45 - Prob. 30PCh. 45 - Prob. 31PCh. 45 - Prob. 32PCh. 45 - Prob. 33PCh. 45 - Prob. 34PCh. 45 - Prob. 35PCh. 45 - Prob. 36PCh. 45 - Prob. 37PCh. 45 - Prob. 41PCh. 45 - Prob. 42PCh. 45 - Prob. 43PCh. 45 - Prob. 44PCh. 45 - Prob. 45PCh. 45 - Prob. 46APCh. 45 - Prob. 47APCh. 45 - Prob. 48APCh. 45 - Prob. 49APCh. 45 - Prob. 51APCh. 45 - Prob. 52APCh. 45 - Prob. 53APCh. 45 - Prob. 54APCh. 45 - Prob. 55APCh. 45 - Prob. 56APCh. 45 - Prob. 57APCh. 45 - Prob. 58APCh. 45 - Prob. 59APCh. 45 - Prob. 60APCh. 45 - Prob. 61APCh. 45 - Prob. 62APCh. 45 - Prob. 63APCh. 45 - Prob. 64APCh. 45 - Prob. 65APCh. 45 - Prob. 66APCh. 45 - Prob. 67APCh. 45 - Prob. 68APCh. 45 - Prob. 69APCh. 45 - Prob. 70APCh. 45 - Prob. 71APCh. 45 - Prob. 72APCh. 45 - Prob. 73AP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- question 4 pleasearrow_forwardA, Explain the importance of reducing exposure dose and time to a patient undergoing a diagnostic X-ray examination. Describe ways to achieve this. B, Calculate the wavelength of the most energetic X-rays produced by tube operating at pd of 1×10^6 V, h= 6.6×10^(-34) J, e=1.6×10^(-19) C, c=3×10^8 ms^(-1)arrow_forwardA small 10-gram source of cobalt-60 is in a vacuum. (a) What is the activity of the cobalt-60source in Bq? (b) What is the actual gamma-ray flux in cm2-s-1 at a point of measurement500 cm from the source due to the cobalt-60 emitted gamma-rays? (c) If the backgroundgamma-ray flux in the vicinity of the 10-g source is 7.8×107cm-2-s-1, what is the totalgamma-ray flux at the point of measurement, including the background? (d) What thicknessof a lead shield in cm would have to be placed between the source and the point ofmeasurement to reduce the total of the background plus the uncollided gamma-ray flux fromthe cobalt-60 source to 1.00×108cm-2-s-1 at that point? (I've attempted part a of the problem and don't know how to continue)arrow_forward
- An alpha particle is accelerated from rest through a potential difference of 35 MV. What is the kinetic energy of the alpha particle, in MeV? Answer:arrow_forwardDetermine the number of neutrons in a bromine nucleus, which has a radius of approximately 5.32 ✕ 10−15 m.arrow_forwardLead (density 11.34 g/cm³) and concrete (density 2.4 g/cm³) are highly effective materias in radiation shielding. a) What thickness of lead in cm is required to reduce the intensity of a 0.2 MeV gamma ray beam by a factor of 1000. b) What is the thickness of concrete in cm equivalent to that thickness of lead?arrow_forward
- imagearrow_forwardGamma-ray detectors like the one described in the preceding problem often use calorimetry to determine gamma-ray energies. Suppose a beam of 100-MeV gamma rays strikes a target with a mass of 2.5 kg and specifi c heat 430 J/(kg # K). How many gamma rays are needed to raise the target’s temperature by 10 mK?arrow_forwardIn a diagnostic x-ray procedure, 5.00 * 1010 photons are absorbed by tissue with a mass of 0.600 kg. The x-ray wavelength is 0.0200 nm. (a) What is the total energy absorbed by the tissue? (b) What is the equivalent dose in rem?arrow_forward
- if a record sample has rate of 44100Hz, how many samples are required to capture 0.25s?arrow_forwardA Geiger–Muller tube is a type of gas‑filled radiation detector. It can detect particles like X‑rays, alpha particles, and beta rays (electrons). This is useful in quantizing the activity of a radioactive source or determining if an area containing radioactive material is safe to enter. If a Geiger counter is filled with 1 mol of argon gas at pressure ?=9502 Pa and temperature ?=22.2 ∘C,T=22.2 ∘C, what is the density ? of the gas in this Geiger tube in grams per cubic centimeter? The atomic mass of argon is ?Ar=39.948 g/mol.arrow_forwardCSDA range Determine the expected range of 2 MeV beta radiation in polyethylene, Aluminium and air. Use the ESTAR database on the NIST website to find the CSDA ranges (to 4 significant figures): R(px) for polyethylene = 9.375E-01 ✓g/cm² R(px) for Al= 1.224E+00 ✓ g/cm² R(px) for air- 1.094E+00 x g/cm² Looking at the 3 values you have found, the statement in the lab notes that the range is 'inversely proportional to the density p of the material and not dependent on its structure or any other properties' is a useful rough approximation because the px values are similar even if not exactly the same The values given are density times thickness (px). To find the actual range (x) we just divide by the density.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningModern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College