Explanation Write the expression for the energy balance equation. E in − E out = Δ E system (I) Here, the total energy entering the system is E in , the total energy leaving the system is E out , and the change in the total energy of the system is Δ E system . Simplify Equation (I) and write energy balance relation of an insulated cylinder. W b,in = Δ U W b,in − Δ U = 0 (II) Here, the boundary work to be done into the system is W b,in and the change in the internal energy is Δ U . Substitute Δ H for W b,in − Δ U in Equation (II). Δ H = 0 Δ H ice + Δ H water = 0 [ m c ( 0 ° C − T 1 ) solid + m h i f + m c ( T 2 − 0 ° C ) liquid ] ice + [ m ( h 2 − h 1 ) ] water = 0 (III) Here, the mass of the ice is m , the heat of fusion of ice is h i f , the specific heat of ice at liquid state is c , the initial temperature of ice is T 1 , the final temperature of ice is T 2 , the initial specific enthalpy of ice is h 1 , and the final specific enthalpy of ice is h 2 . Write the expression of initial specific volume of a two-phase system for insulated cylinder device. v 1 = v f + x v f g = v f + x ( v g − v f ) (IV) Here, the specific volume of ice for insulated cylinder device is v f , the specific volume of ice for insulated cylinder device is v g , the specific volume change upon vaporization for insulated cylinder device is v f g , and the quality of final state for insulated cylinder device is x . Write the expression of initial specific internal energy of a two-phase system for piston-cylinder device. u 1 = u f + x u f g (V) Here, the specific internal energy of ice for insulated cylinder device is u f , the specific internal energy change upon vaporization for insulated cylinder device is u f g , and the quality of final state for insulated cylinder device is x . Determine the initial specific volume of the refrigerant. v 1 = V 1 m m = V 1 v 1 (VI) Here, the mass of a ice is m and the initial volume of the saturated liquid-vapour mixture is V 1 . Conclusion: From the Table A-3 “Properties of common liquids, solids and foods”, obtain the value of specific heat of ice at 0 C and 120 C temperature as 2.11 kJ / kg ° C and 4.18 kJ / kg ° C . From the Table A-4 “Saturated water”, obtain the value of specific volume and enthalpy of saturated liquid, vapour and change upon vaporization for insulated cylinder device. At final temperature of water as 120 ° C . v f = 0.001060 v g = 0.89133 m 3 / kg h f = 503.81 h f g = 2202.1 kJ / kg Substitute 0.001060 for v f , 0.2 for x , and 0.89133 m 3 / kg for v g in Equation (I) v 1 = ( 0.001060 ) + ( 0.2 ) × ( 0.89133 m 3 / kg − 0.001060 ) = ( 0.001060 ) + ( 0

8th Edition

ISBN: 9780073398174

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

See similar textbooks

Concept explainers

Work and Heat Transfer

It is generally related to thermal engineering which tells about the use, creation, conversion and transfer of heat energy between the systems. It is also considered that to transfer heat from one source to another, transfer of masses is also required. T…

Videos

Question

Chapter 4.5, Problem 119RP

To determine

The amount of ice that needs to be added in an insulated cylinder.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 4.5, Problem 118RP

Chapter 4.5, Problem 120RP

Students have asked these similar questions

Exposure to high concentrations of gaseous ammonia can cause lung damage. The acceptable short term ammonia exposure level set by the occupational safety and health administration is 35 ppm for 15 min. consider a vessel filled with gaseous ammonia at 30 mol/L and 10 cm diameter circular plastic plug with thickeness of 2 mm is used to contain the ammonia inside the vessel. the ventilation system is capable of keeping the room safe with fresh air, provded that the rate of ammonia being release is below .2 mg/s. if the diffusion coefficient of ammonia through the plug is 1.3*10^-10 m^2/s, determine whether or not the plug can safelt contain the ammonia inside the vessel.

The state of stress at a point is σ = -8.00 kpsi, σy = 12.00 kpsi, σ% = -18.00 kpsi, Try = 7.00 kpsi, Tyz = 4.000 kpsi, and Tzx = -18.00 kpsi. Determine the principal stresses. The principal normal stress σ1 is determined to be kpsi. The principal normal stress σ2 is determined to be The principal normal stress σ3 is determined to be kpsi. kpsi. The principal shear stress T₁ T1/2 is determined to be kpsi. The principal shear stress 72/ is determined to be [ kpsi. The principal shear stress T1/3 is determined to be kpsi.

The constant 180 N-m counterclockwise couple acts on the L-shaped rod ABC, which rotates freely in the vertical plane about the pin at A. At this moment, the angular velocity of the rod is 2 rad/s counterclockwise. Determine the angular acceleration of the rod and the reactions at A in the position shown. Answer: a=1.7 rad/s², Ax = 25.3 N, Ay = 603 N 180 N-m 1.2 m 24 kg 20 kg B 1.0 m

Chapter 4 Solutions

Thermodynamics: An Engineering Approach

Ch. 4.5 - An ideal gas at a given state expands to a fixed...Ch. 4.5 - Nitrogen at an initial state of 300 K, 150 kPa,...Ch. 4.5 - 4–3 The volume of 1 kg of helium in a...Ch. 4.5 - 4–4E Calculate the total work, in Btu, for process...Ch. 4.5 - 4–5 A piston–cylinder device initially contains...Ch. 4.5 - A pistoncylinder device with a set of stops...Ch. 4.5 - 4–7 A piston–cylinder device initially contains...Ch. 4.5 - 4–8 A mass of 5 kg of saturated water vapor at 300...Ch. 4.5 - 1 m3 of saturated liquid water at 200C is expanded...Ch. 4.5 - A gas is compressed from an initial volume of 0.42...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.