Explanation Given information: The function f ( x ) = x 2 + 1 x is concave down for x < 0 and concave up for x> 0. We have: f ( x ) = x 2 + 1 x . An inflection point is a point in a graph at which the concavity changes. To find the inflection points of f , we need to use f ″ . f ( x ) = x 2 + 1 x f ′ ( x ) = x ( 2 x ) − 1 ( x 2 + 1 ) x 2 = 2 x 2 − x 2 − 1 x 2

4th Edition

ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.4, Problem 5PQ

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To explain:whether there is an inflection point at x = 0 or not.

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Chapter 4.4, Problem 4PQ

Chapter 4.4, Problem 6PQ

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Chapter 4 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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whether there is an inflection point at x = 0 or not.

Solution Summary: The author explains that there is no inflection point at x=0.

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Chapter 4 Solutions