Explanation Let sin θ = L 2 R .then L = 2 R sin θ h = R − R cos θ = R ( 1 − cos θ ) = 1 2 L sin To determine b) To find out the maximum vertical displacement for L + m = 2 R θ and conclude that sin θ θ = L L + m .

4th Edition

ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.7, Problem 32E

To determine

a)

To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

To determine

b)

To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.

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Chapter 4.7, Problem 31E

Chapter 4.7, Problem 33E

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Evaluate the limit along the stated paths, or type "DNE" if the limit Does Not Exist: lim xy+y³ (x,y)(0,0) x²+ y² Along the path = = 0: Along the path y = = 0: Along the path y = 2x:

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A graph of the function f is given below: Study the graph of ƒ at the value given below. Select each of the following that applies for the value a = 1 Of is defined at a. If is not defined at x = a. Of is continuous at x = a. If is discontinuous at x = a. Of is smooth at x = a. Of is not smooth at = a. If has a horizontal tangent line at = a. f has a vertical tangent line at x = a. Of has a oblique/slanted tangent line at x = a. If has no tangent line at x = a. f(a + h) - f(a) lim is finite. h→0 h f(a + h) - f(a) lim h->0+ and lim h h->0- f(a + h) - f(a) h are infinite. lim does not exist. h→0 f(a+h) - f(a) h f'(a) is defined. f'(a) is undefined. If is differentiable at x = a. If is not differentiable at x = a.

Chapter 4 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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a) To find out the maximum vertical displacement for L = 2 R sin θ and conclude that h = L ( 1 − cos θ ) 2 sin θ .

Solution Summary: The author explains the solution obtained as L(1-mathrmcos

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a)

To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

b)

To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.

Want to see the full answer?

Chapter 4 Solutions

a) To find out the maximum vertical displacement for L = 2 R sin θ and conclude that h = L ( 1 − cos θ ) 2 sin θ .

Solution Summary: The author explains the solution obtained as L(1-mathrmcos

Videos

a) To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

b) To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.

Want to see the full answer?

Chapter 4 Solutions

a)

To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

b)

To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.