Explanation Given: d d t ( t − t 2 3 ) Apply the chain rule : d f ( u ) d x = d f d u × d u d x = d d u ( u 3 ) d d t ( t − t 2 ) d d u ( u 3 ) Apply radical rule : a n = a 1 n = d d u ( u 1 3 ) Apply the Power Rule : d d x ( x a ) = a × x a − 1 = 1 3 u 1 3 − 1 = 1 3 u 1 3 − 1 u 1 3 − 1 = u − 2 3 = 1 3 u − 2 3 Apply exponent rule : a − b = 1 a b u − 2 3 = 1 u 2 3 = 1 3 × 1 u 2 3 Multiply fractions : a b × c d = a × c b × d = 1 × 1 3 u 2 3

4th Edition

ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.2, Problem 42E

To determine

Find the critical point and endpoint at the minimum and maximum value of the function of y=(t−t2)−2x, [−1, 2].

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Chapter 4.2, Problem 41E

Chapter 4.2, Problem 43E

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Chapter 4 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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Find the critical point and endpoint at the minimum and maximum value of the function of y = ( t − t 2 ) − 2 x , [ − 1 , 2 ] .

Solution Summary: The author explains how to determine the critical point and endpoint at the minimum and maximum value of the function y=(t-t2)-2sqrt

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Find the critical point and endpoint at the minimum and maximum value of the function of y=(t−t2)−2x, [−1, 2].

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Chapter 4 Solutions

Find the critical point and endpoint at the minimum and maximum value of the function of y = ( t − t 2 ) − 2 x , [ − 1 , 2 ] .

Solution Summary: The author explains how to determine the critical point and endpoint at the minimum and maximum value of the function y=(t-t2)-2sqrt

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Find the critical point and endpoint at the minimum and maximum value of the function of y=(t−t2)−2x, [−1, 2].

Want to see the full answer?

Chapter 4 Solutions

Find the critical point and endpoint at the minimum and maximum value of the function of y=(t−t2)−2x, [−1, 2].