Explanation Given Info: f ( θ ) = sin θ − 0.8 θ Formula Used: x n + 1 = x n − f ( x n ) f ' ( x n ) Calculation: f ' ( θ ) = cos θ − 0.8 θ n + 1 = θ n − f ( θ ) f ' ( θ ) θ n + 1 = θ n − sin θ − 0

4th Edition

ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.7, Problem 18E

To determine

To find the approximate positive root of f(θ)=sinθ−0.8θ

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Chapter 4.7, Problem 17E

Chapter 4.7, Problem 19E

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6. The largest interval in which the solution of (cos t)y′′ +t^2y′ − (5/t)y = e^t/(t−3) , y(1) = 2, y′(1) = 0is guaranteed to exist by the Existence and Uniqueness Theorem is:A. (0, ∞) B. (π/2, 3) C. (0,π/2) D. (0, π) E. (0, 3)

12. For the differential equation in the previous question, what is the correct form for a particularsolution?A. yp = Ae^t + Bt^2 B. yp = Ae^t + Bt^2 + Ct + DC. yp = Ate^t + Bt^2 D. yp = Ate^t + Bt^2 + Ct + D Previous differential equation y′′ − 4y′ + 3y = e^t + t^2

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Chapter 4 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

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To find the approximate positive root of f ( θ ) = sin θ − 0.8 θ

Solution Summary: The author explains how to determine the approximate positive root of f(theta)=mathrmsin

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To find the approximate positive root of f(θ)=sinθ−0.8θ

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Chapter 4 Solutions