Explanation Given: sin θ 1 v 1 = sin θ 2 v 2 Where, v 1 and v 2 is the velocity of light in air and water respectively. Calculation: Let, a and b be the distance travelled by the light in the air and water respectively. Time taken by the light to travel from the point A to point B, f ( x ) = a v 1 + b v 2 From the triangles in the figure, we can write the above expressions as follows: f ( x ) = x 2 + h 1 2 v 1 + ( L − x ) 2 + h 2 2 v 2 Differentiating the above equation and equating to zero, we get f ' ( x ) = x v 1 x 2 + h 1 2 − ( L − x ) v 2 ( L − x ) 2 + h 2 2 x v 1 x 2 + h 1 2 − (

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Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.6, Problem 56E

To determine

To prove that Snell’s Law of refraction, sinθ1v1 =sinθ2v2.

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Chapter 4.6, Problem 55E

Chapter 4.6, Problem 57E

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Chapter 4 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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To prove that Snell’s Law of refraction, sin θ 1 v 1 = sin θ 2 v 2 .

Solution Summary: The author explains how to determine the Snell's Law of retion by using mathrmsintheta, where a and b are the distance travelled

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To prove that Snell’s Law of refraction, sinθ1v1 =sinθ2v2.

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Chapter 4 Solutions