Explanation The right triangle formed by the right half of the rectangle and its “roof”. This triangle has hypotenuse s . y − h b 2 = h x or y = b h 2 x + h . s 2 = ( b 2 + x ) 2 + y 2 = ( b 2 + x ) 2 + ( b h x + h ) 2 ( b 2 + x ) + 2 ( b h 2 x + 8 ) ( − b h 2 x 2 ) = 0 2 ( b 2 + x ) + 2 h x ( b 2 + x ) ( − b h x 2 ) = 0 2 ( b 2 + x ) ( 1 − b h 2 x 3 ) = 0 x = b 1 3 h 2 3 2 1 3 s

4th Edition

ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.6, Problem 71E

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The problem is to put a “roof” of side s on an attic room of height h and width b. Find the smallest length s for which this is possible if b and h.

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Chapter 4.6, Problem 70E

Chapter 4.6, Problem 72E

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Chapter 4 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

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The problem is to put a “roof” of side s on an attic room of height h and width b . Find the smallest length s for which this is possible if b and h .

Solution Summary: The author explains the problem of putting a "roof" of side s on an attic room.

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The problem is to put a “roof” of side s on an attic room of height h and width b. Find the smallest length s for which this is possible if b and h.

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Chapter 4 Solutions