
Organic Chemistry
8th Edition
ISBN: 9781305580350
Author: William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 4.3, Problem 4.5P
For each value of Ka, calculate the corresponding value of pKa. Which compound is the stronger acid?
- (a) Acetic add, Ka = 1.74 × 10–5
- (b) Chloroacetic acid, Ka= 1.38 × 10–3
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Michael Reactions
19.52 Draw the products from the following Michael addition reactions.
1.
H&C CH
(a)
i
2. H₂O*
(b)
OEt
(c)
EtO
H₂NEt
(d)
ΕΙΟ
+
1. NaOEt
2. H₂O'
H
H
1. NaOEt
2. H₂O*
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
+ More...
Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
Chapter 4 Solutions
Organic Chemistry
Ch. 4.2 - For each conjugate acid-base pair, identify the...Ch. 4.2 - Write these reactions as proton-transfer...Ch. 4.2 - Following is a structural formula for guanidine,...Ch. 4.2 - Write an equation to show the proton transfer...Ch. 4.3 - For each value of Ka, calculate the corresponding...Ch. 4.4 - Predict the position of equilibrium and calculate...Ch. 4.5 - Calculate Keq for a reaction with G0 = 17.1 kJ/mol...Ch. 4.6 - Acid-Base Equilibria Many factors contribute to...Ch. 4.6 - What is the relative trend in acidity and pKa of...Ch. 4.7 - Write an equation for the reaction between each...
Ch. 4 - For each conjugate acid-base pair, identify the...Ch. 4 - Complete a net ionic equation for each...Ch. 4 - Arrange the compounds in each set in order of...Ch. 4 - Prob. 4.12PCh. 4 - In acetic acid, CH3COOH, the OH hydrogen is more...Ch. 4 - Which has the larger numerical value? (a) The pKa...Ch. 4 - In each pair, select the stronger acid. (a)...Ch. 4 - Arrange the compounds in each set in order of...Ch. 4 - Arrange the compounds in each set in order of...Ch. 4 - If the G for a reaction is 4.5 kcal/mol at 298 K,...Ch. 4 - Calculate the Keq for the following reactions from...Ch. 4 - Prob. 4.20PCh. 4 - Answer true or false to the following statements...Ch. 4 - In each of the following three reaction coordinate...Ch. 4 - The acid-base chemistry reaction of barium...Ch. 4 - Unless under pressure, carbonic acid (H2CO3) in...Ch. 4 - Prob. 4.25PCh. 4 - Acetic acid, CH3COOH, is a weak organic acid, pKa...Ch. 4 - Benzoic acid, C6H5COOH (pKa 4.19), is only...Ch. 4 - Prob. 4.28PCh. 4 - One way to determine the predominant species at...Ch. 4 - Will acetylene react with sodium hydride according...Ch. 4 - Prob. 4.31PCh. 4 - For each equation, label the Lewis acid and the...Ch. 4 - Complete the equation for the reaction between...Ch. 4 - Each of these reactions can be written as a Lewis...Ch. 4 - The sec-butyl cation can react as both a...Ch. 4 - Prob. 4.36APCh. 4 - Prob. 4.37APCh. 4 - Prob. 4.38APCh. 4 - Explain why the hydronium ion, H3O+, is the...Ch. 4 - What is the strongest base that can exist in...Ch. 4 - Prob. 4.42APCh. 4 - Prob. 4.43APCh. 4 - Methyl isocyanate, CH3N=C=O, is used in the...Ch. 4 - Offer an explanation for the following...Ch. 4 - Prob. 4.46APCh. 4 - Alcohols (Chapter 10) are weak organic acids, pKa...Ch. 4 - As we shall see in Chapter 19, hydrogens on a...Ch. 4 - 2,4-Pentanedione is a considerably stronger acid...Ch. 4 - Write an equation for the acid-base reaction...Ch. 4 - Prob. 4.51APCh. 4 - Prob. 4.52APCh. 4 - Prob. 4.53APCh. 4 - Following is a structural formula for imidazole, a...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJarrow_forwardA covalent bond is the result of the a) b) c) d) e) overlap of two half-filled s orbitals overlap of a half-filled s orbital and a half-filled p orbital overlap of two half-filled p orbitals along their axes parallel overlap of two half-filled parallel p orbitals all of the abovearrow_forwardCan the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C T Add/Remove step X ноarrow_forward
- Which one of the following atoms should have the largest electron affinity? a) b) c) d) 으으 e) 1s² 2s² 2p6 3s¹ 1s² 2s² 2p5 1s² 2s² 2p 3s² 3p² 1s² 2s 2p 3s² 3p6 4s2 3ds 1s² 2s² 2p6arrow_forwardAll of the following are allowed energy levels except _. a) 3f b) 1s c) 3d d) 5p e) 6sarrow_forwardA student wants to make the following product in good yield from a single transformation step, starting from benzene. Add any organic reagents the student is missing on the left-hand side of the arrow, and any addition reagents that are necessary above or below the arrow. If this product can't be made in good yield with a single transformation step, check the box below the drawing area. Note for advanced students: you may assume that an excess of benzene is used as part of the reaction conditions. : ☐ + I X This product can't be made in a single transformation step.arrow_forward
- Ppplllleeeaaasssseeee helllppp wiithhh thisss Organic chemistryyyyyy I talked like this because AI is very annoyingarrow_forwardName the family to which each organic compound belongs. The first answer has been filled in for you. compound CH₂ || CH3-C-NH2 0 ။ CH3-C-CH₂ CH=O–CH=CH, CH₂ HO CH2-CH2-CH-CH3 family amine Darrow_forward1b. Br LOHarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning

Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning

Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning

Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning


Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning

Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
General Chemistry | Acids & Bases; Author: Ninja Nerd;https://www.youtube.com/watch?v=AOr_5tbgfQ0;License: Standard YouTube License, CC-BY