Explanation Given Information: A total of 120 feet is to be fenced by a homeowner for his dog. The table is as follows: Width Length Area Ordered pair ( w , A ) 5 10 15 20 25 30 35 40 45 50 Graph: Consider that 120 feet is to be fenced by a homeowner for his dog and the table, Width Length Area Ordered pair ( w , A ) 5 10 15 20 25 30 35 40 45 50 The perimeter of the rectangle is given by: Perimeter = 2 ( l + w ) Where, l is the length and w is the width of the rectangle. When the width is 5 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 5 ) 120 = 2 l + 10 110 = 2 l 55 = l The length is 55 feet. When the width is 10 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 10 ) 120 = 2 l + 20 100 = 2 l 50 = l The length is 50 feet. When the width is 15 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 15 ) 120 = 2 l + 30 90 = 2 l 45 = l The length is 45 feet. When the width is 20 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 20 ) 120 = 2 l + 40 80 = 2 l 40 = l The length is 40 feet. When the width is 25 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 25 ) 120 = 2 l + 50 70 = 2 l 35 = l The length is 35 feet. When the width is 30 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 30 ) 120 = 2 l + 60 60 = 2 l 30 = l The length is 30 feet. When the width is 35 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 35 ) 120 = 2 l + 70 50 = 2 l 25 = l The length is 25 feet. When the width is 40 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 40 ) 120 = 2 l + 80 40 = 2 l 20 = l The length is 20 feet. When the width is 45 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 45 ) 120 = 2 l + 90 30 = 2 l 15 = l The length is 15 feet. When the width is 50 feet, Substitute the values in the formula and evaluate, 120 = 2 ( l + 50 ) 120 = 2 l + 100 20 = 2 l 10 = l The length is 10 feet. Complete the second column of the table as, Width Length Area Ordered pair ( w , A ) 5 55 10 50 15 45 20 40 25 35 30 30 35 25 40 20 45 15 50 10 The area of the rectangle is given by: Area = l × w Where, l is the length and w is the width of the rectangle. When the width is 5 feet and the length is 55 feet, Substitute the values in the formula and evaluate, Area = 5 × 55 = 275 The area is 275 feet 2 . When the width is 10 feet and the length is 50 feet, Substitute the values in the formula and evaluate, Area = 10 × 50 = 500 The area is 500 feet 2 . When the width is 15 feet and the length is 45 feet, Substitute the values in the formula and evaluate, Area = 15 × 45 = 675 The area is 675 feet 2 . When the width is 20 feet and the length is 40 feet, Substitute the values in the formula and evaluate, Area = 20 × 40 = 800 The area is 800 feet 2

1st Edition

ISBN: 9781259218859

Author: David Sobecki Professor, Brian A. Mercer

Publisher: McGraw-Hill Education

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Question

Chapter 4.3, Problem 1T

To determine

To graph: The scatter plot showing the width and the area of the play area obtained by completing the following table that shows the length of a play area when it is given that 120 feet is to be fenced by a homeowner for his dog.

Width Length Area Ordered pair (w,A)

5

10

15

20

25

30

35

40

45

50

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Chapter 4.3, Problem 15G

Chapter 4.3, Problem 1R

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To graph: The scatter plot showing the width and the area of the play area obtained by completing the following table that shows the length of a play area when it is given that 120 feet is to be fenced by a homeowner for his dog. Width Length Area Ordered pair ( w , A ) 5 10 15 20 25 30 35 40 45 50

Solution Summary: The author analyzes the scatter plot showing the width and the area of the play area when 120 feet is to be fenced by a homeowner for his dog.

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Chapter 4 Solutions

Width	Length	Area	Ordered pair (w,A)
5
10
15
20
25
30
35
40
45
50

To graph: The scatter plot showing the width and the area of the play area obtained by completing the following table that shows the length of a play area when it is given that 120 feet is to be fenced by a homeowner for his dog. Width Length Area Ordered pair ( w , A ) 5 10 15 20 25 30 35 40 45 50

Solution Summary: The author analyzes the scatter plot showing the width and the area of the play area when 120 feet is to be fenced by a homeowner for his dog.

Videos

To graph: The scatter plot showing the width and the area of the play area obtained by completing the following table that shows the length of a play area when it is given that 120 feet is to be fenced by a homeowner for his dog. Width Length Area Ordered pair (w,A) 5 10 15 20 25 30 35 40 45 50

Want to see the full answer?

Chapter 4 Solutions