Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
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Chapter 4, Problem D4.15P
To determine
Value of peak to peak sine wave voltage.
The value of resistance required.
The value of peak diode current.
Peak reverse voltage across the diode.
If resistor can be specified to one significant digit and peak to peak voltage only to the nearest volt,
Which design will guarantee the required charging current?
Fraction of the cycle does diode current flow.
Average diode current.
Peak diode current.
Peak reverse voltage across the diode.
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For a band-rejection filter, the response drops below this half power point at two locations as visualised in Figure 7, we need to find these
frequencies. Let's call the lower frequency-3dB point as fr and the higher frequency -3dB point fH. We can then find out the bandwidth as
f=fHfL, as illustrated in Figure 7.
0dB
Af
-3 dB
Figure 7. Band reject filter response diagram
Considering your AC simulation frequency response and referring to Figure 7, measure the following from your AC simulation. 1% accuracy:
(a) Upper-3db Frequency (fH) =
Hz
(b) Lower-3db Frequency (fL) =
Hz
(c) Bandwidth (Aƒ) =
Hz
(d) Quality Factor (Q) =
P 4.4-21 Determine the values of the node voltages V1, V2, and
v3 for the circuit shown in Figure P 4.4-21.
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1. What is the theoretical attenuation of the output voltage at the resonant frequency? Answer to within 1%, or enter 0, or infinity (as “inf”)
Attenuation =
Chapter 4 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 4.1 - Prob. 4.1ECh. 4.1 - Prob. 4.2ECh. 4.1 - Prob. 4.3ECh. 4.1 - Prob. 4.4ECh. 4.1 - Prob. 4.5ECh. 4.2 - Prob. 4.6ECh. 4.2 - Prob. 4.7ECh. 4.2 - Prob. 4.8ECh. 4.2 - Prob. 4.9ECh. 4.3 - Prob. 4.10E
Ch. 4.3 - Prob. D4.11ECh. 4.3 - Prob. 4.12ECh. 4.3 - Prob. 4.13ECh. 4.3 - Prob. 4.14ECh. 4.3 - Prob. D4.15ECh. 4.4 - Prob. 4.16ECh. 4.4 - Prob. 4.17ECh. 4.4 - Prob. 4.18ECh. 4.5 - Prob. 4.19ECh. 4.5 - Prob. 4.20ECh. 4.5 - Prob. 4.21ECh. 4.5 - Prob. 4.22ECh. 4.5 - Prob. 4.23ECh. 4.5 - Prob. 4.24ECh. 4.5 - Prob. 4.25ECh. 4.6 - Prob. 4.26ECh. 4.6 - Prob. 4.27ECh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. D4.7PCh. 4 - Prob. D4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. D4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. D4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. D4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. D4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. D4.56PCh. 4 - Prob. D4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. D4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. D4.63PCh. 4 - Prob. D4.64PCh. 4 - Prob. D4.65PCh. 4 - Prob. D4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. D4.73PCh. 4 - Prob. D4.74PCh. 4 - Prob. D4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. D4.80PCh. 4 - Prob. D4.81PCh. 4 - Prob. D4.82PCh. 4 - Prob. D4.83PCh. 4 - Prob. D4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88PCh. 4 - Prob. 4.89PCh. 4 - Prob. 4.90PCh. 4 - Prob. 4.91PCh. 4 - Prob. 4.92PCh. 4 - Prob. 4.93PCh. 4 - Prob. 4.94PCh. 4 - Prob. 4.95PCh. 4 - Prob. 4.96PCh. 4 - Prob. 4.97P
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- What is the settling time for your output signal (BRF_OUT)? For this question, We define the settling time as the period of time it has taken for the output to settle into a steady state - ie when your oscillation first decays (aka reduces) to less than approximately 1/20 (5%) of the initial value. (a) Settling time = 22 μs Your last answer was interpreted as follows: Incorrect answer. Check 22 222 What is the peak to peak output voltage (BRF_OUT pp) at the steady state condition? You may need to use the zoom function to perform this calculation. Select a time point that is two times the settling time you answered in the question above. Answer to within 10% accuracy. (a) BRF_OUT pp= mVpp As you may have noticed, the output voltage amplitude is a tiny fraction of the input voltage, i.e. it has been significantly attenuated. Calculate the attenuation (decibels = dB) in the output signal as compared to the input based on the formula given below. Answer to within 1% accuracy.…arrow_forwardmy previous answers for a,b,d were wrong a = 1050 b = 950 d=9.99 c was the only correct value i got previously c = 100hz is correctarrow_forwardV₁(t) ww ZRI ZLI ZL2 ZTH Zci VTH Zc21 Figure 8. Circuit diagram showing calculation approach for VTH and Z TH we want to create a blackbox for the red region, we want to use the same input signal conditions as previously the design of your interference ector circuit: Sine wave with a 1 Vpp, with a frequency of 100 kHz (interference) Square wave with 2.4Vpp, with a frequency of 10 kHz (signal) member an AC Thevenin equivalent is only valid at one frequency. We have chosen to calculate the Thevenin equivalent circuit (and therefore the ackbox) at the interference frequency (i.e. 100 kHz), and the signal frequency (i.e. 10 kHz) as these are the key frequencies to analyse. Your boss is assured you that the waveform converter module has been pre-optimised to the DAB Receiver if you use the recommended circuit topology.arrow_forward
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