The value of current I by using Ohm’s Law.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 1, Problem 1.1P

(a)

To determine

The value of current I by using Ohm’s Law.

(a)

Expert Solution

Answer to Problem 1.1P

I=5mA

Explanation of Solution

Given information:

V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

(b)

To determine

The value of resistanceR by using Ohm’s Law.

(b)

Expert Solution

Answer to Problem 1.1P

R=5kA

Explanation of Solution

Given information:

I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

(c)

To determine

The value of voltage V by using Ohm’s Law.

(c)

Expert Solution

Answer to Problem 1.1P

V=1V

Explanation of Solution

Given information:

I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IRV=(10× 103)(0.1× 10 −3)V=1V

(d)

To determine

The value of current I by using Ohm’s Law.

(d)

Expert Solution

Answer to Problem 1.1P

I=10mA

Explanation of Solution

Given information:

V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR1=I(100)I=1100AI=10mA

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

64) answer just two from three the following terms: A) Design ADC using the successive method if the Vmax=(3) volt, Vmin=(-2) volt, demonstrate the designing system for vin-1.2 volt. Successive Approximation ADC Input Voltage-1.1 V -4-3.5-3 -2.5 -2 -1.5 +1 -0.5 0 0.5 1 1.5 2 2.5 3 3.5 1 T -8 -7 -6 -5 -3 +2 -1 0 1 2 3 4 5 6 7 X=1??? 1st guess: -0.25 V (too high) X=11?? 2nd guess: -2.25 V (too low) 3rd guess: -1.25 V (too low) X=1110 X=111? 4th guess: -0.75 V (too high) Make successive guesses and use a comparator to tell whether your guess is too high or too low. Each guess determines one bit of the answer and cuts the number of remaining possibilities in half.

Datacommunıcatıonin a commuinaction ASYNCHRONOUS TRANSMİTİON is used in this transmistion 7-bit chatacter will be transfered even parity will be used ,stop element is as 1,5 bits a)=select a chracter yourself and dısplay the signal transfered in this transmission , and calculate the overhead in this transmision

(i) Find the inverse z-transform of the system H(z) = for the following regions of convergence. Write in the final answer for each case in the allocated rectangular box below (a) |z| 3 (c) 1

Answer 2

Question

Chapter 1, Problem 1.1P

(a)

To determine

The value of current I by using Ohm’s Law.

(a)

Expert Solution

Answer to Problem 1.1P

I=5mA

Explanation of Solution

Given information:

V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

(b)

To determine

The value of resistanceR by using Ohm’s Law.

(b)

Expert Solution

Answer to Problem 1.1P

R=5kA

Explanation of Solution

Given information:

I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

(c)

To determine

The value of voltage V by using Ohm’s Law.

(c)

Expert Solution

Answer to Problem 1.1P

V=1V

Explanation of Solution

Given information:

I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IRV=(10× 103)(0.1× 10 −3)V=1V

(d)

To determine

The value of current I by using Ohm’s Law.

(d)

Expert Solution

Answer to Problem 1.1P

I=10mA

Explanation of Solution

Given information:

V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR1=I(100)I=1100AI=10mA

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 1, Problem 1.1P

(a)

To determine

The value of current I by using Ohm’s Law.

(a)

Expert Solution

Answer to Problem 1.1P

I=5mA

Explanation of Solution

Given information:

V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

(b)

To determine

The value of resistanceR by using Ohm’s Law.

(b)

Expert Solution

Answer to Problem 1.1P

R=5kA

Explanation of Solution

Given information:

I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

(c)

To determine

The value of voltage V by using Ohm’s Law.

(c)

Expert Solution

Answer to Problem 1.1P

V=1V

Explanation of Solution

Given information:

I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IRV=(10× 103)(0.1× 10 −3)V=1V

(d)

To determine

The value of current I by using Ohm’s Law.

(d)

Expert Solution

Answer to Problem 1.1P

I=10mA

Explanation of Solution

Given information:

V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR1=I(100)I=1100AI=10mA

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 1, Problem 1.1P

(a)

To determine

The value of current I by using Ohm’s Law.

(a)

Expert Solution

Answer to Problem 1.1P

I=5mA

Explanation of Solution

Given information:

V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

(b)

To determine

The value of resistanceR by using Ohm’s Law.

(b)

Expert Solution

Answer to Problem 1.1P

R=5kA

Explanation of Solution

Given information:

I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

(c)

To determine

The value of voltage V by using Ohm’s Law.

(c)

Expert Solution

Answer to Problem 1.1P

V=1V

Explanation of Solution

Given information:

I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IRV=(10× 103)(0.1× 10 −3)V=1V

(d)

To determine

The value of current I by using Ohm’s Law.

(d)

Expert Solution

Answer to Problem 1.1P

I=10mA

Explanation of Solution

Given information:

V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR1=I(100)I=1100AI=10mA

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 1, Problem 1.1P

(a)

To determine

The value of current I by using Ohm’s Law.

(a)

Expert Solution

Answer to Problem 1.1P

I=5mA

Explanation of Solution

Given information:

V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

(b)

To determine

The value of resistanceR by using Ohm’s Law.

(b)

Expert Solution

Answer to Problem 1.1P

R=5kA

Explanation of Solution

Given information:

I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

(c)

To determine

The value of voltage V by using Ohm’s Law.

(c)

Expert Solution

Answer to Problem 1.1P

V=1V

Explanation of Solution

Given information:

I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IRV=(10× 103)(0.1× 10 −3)V=1V

(d)

To determine

The value of current I by using Ohm’s Law.

(d)

Expert Solution

Answer to Problem 1.1P

I=10mA

Explanation of Solution

Given information:

V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR1=I(100)I=1100AI=10mA

Answer 6

Chapter 1, Problem 1.1P

(a)

To determine

The value of current I by using Ohm’s Law.

(a)

Expert Solution

Answer to Problem 1.1P

I=5mA

Explanation of Solution

Given information:

V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

Answer 7

Chapter 1, Problem 1.1P

(a)

To determine

The value of current I by using Ohm’s Law.

Answer 8

(a)

Expert Solution

Answer to Problem 1.1P

I=5mA

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given information:

V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

Answer 13

(b)

To determine

The value of resistanceR by using Ohm’s Law.

(b)

Expert Solution

Answer to Problem 1.1P

R=5kA

Explanation of Solution

Given information:

I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

Answer 14

(b)

To determine

The value of resistanceR by using Ohm’s Law.

Answer 15

(b)

Expert Solution

Answer to Problem 1.1P

R=5kA

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given information:

I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

Answer 20

(c)

To determine

The value of voltage V by using Ohm’s Law.

(c)

Expert Solution

Answer to Problem 1.1P

V=1V

Explanation of Solution

Given information:

I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IRV=(10× 103)(0.1× 10 −3)V=1V

Answer 21

(c)

To determine

The value of voltage V by using Ohm’s Law.

Answer 22

(c)

Expert Solution

Answer to Problem 1.1P

V=1V

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given information:

I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IRV=(10× 103)(0.1× 10 −3)V=1V

Answer 27

(d)

To determine

The value of current I by using Ohm’s Law.

(d)

Expert Solution

Answer to Problem 1.1P

I=10mA

Explanation of Solution

Given information:

V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR1=I(100)I=1100AI=10mA

Answer 28

(d)

To determine

The value of current I by using Ohm’s Law.

Answer 29

(d)

Expert Solution

Answer to Problem 1.1P

I=10mA

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given information:

V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

V=IR1=I(100)I=1100AI=10mA

Answer 34

Ch. 1.1 - Prob. 1.1E Ch. 1.1 - Prob. 1.2E Ch. 1.1 - Prob. 1.3E Ch. 1.1 - Prob. 1.4E Ch. 1.2 - Prob. 1.5E Ch. 1.2 - Prob. 1.6E Ch. 1.2 - Prob. 1.7E Ch. 1.2 - Prob. 1.8E Ch. 1.3 - Prob. 1.9E Ch. 1.4 - Prob. 1.10E

The value of current I by using Ohm’s Law.

Concept explainers

Videos

The value of current I by using Ohm’s Law.

Answer to Problem 1.1P

Explanation of Solution

The value of resistanceR by using Ohm’s Law.

Answer to Problem 1.1P

Explanation of Solution

The value of voltage V by using Ohm’s Law.

Answer to Problem 1.1P

Explanation of Solution

The value of current I by using Ohm’s Law.

Answer to Problem 1.1P

Explanation of Solution

Want to see more full solutions like this?

Chapter 1 Solutions