Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 4.85P
To determine
The values of
Average output voltage when
Frequency = 1kHz, Average = 0, Amplitude = 5V.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
4.39 A designer has a supply of diodes for which a current
of 2 mA flows at 0.7 V. Using a 1-mA current source, the
designer wishes to create a reference voltage of 1.3 V. Suggest
a combination of series and parallel diodes that will do the
job as well as possible. How many diodes are needed? What
voltage is actually achieved?
Given the circuit design for a Zener diode regulator in the previous question, what is the maximum power that will be dissipated by the Rs resistor? You are told that the source voltage Vs varies from 6 V to 13 V, the load current il varies between 2 mA and 47 mA, and the diode is an ideal 4 V Zener diode. You will need to recalculate the maximum allowable resistance Rs with your new values, as part of this question. Please enter your answer to 3 significant figures, and in Watts.
Q4: Consider a Zener diode with a nominal voltage (10v @ 10mA) and a resistance of 50 ohm. Calculate the
expected Zener voltage if the diode current is halved?
Chapter 4 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 4.1 - Prob. 4.1ECh. 4.1 - Prob. 4.2ECh. 4.1 - Prob. 4.3ECh. 4.1 - Prob. 4.4ECh. 4.1 - Prob. 4.5ECh. 4.2 - Prob. 4.6ECh. 4.2 - Prob. 4.7ECh. 4.2 - Prob. 4.8ECh. 4.2 - Prob. 4.9ECh. 4.3 - Prob. 4.10E
Ch. 4.3 - Prob. D4.11ECh. 4.3 - Prob. 4.12ECh. 4.3 - Prob. 4.13ECh. 4.3 - Prob. 4.14ECh. 4.3 - Prob. D4.15ECh. 4.4 - Prob. 4.16ECh. 4.4 - Prob. 4.17ECh. 4.4 - Prob. 4.18ECh. 4.5 - Prob. 4.19ECh. 4.5 - Prob. 4.20ECh. 4.5 - Prob. 4.21ECh. 4.5 - Prob. 4.22ECh. 4.5 - Prob. 4.23ECh. 4.5 - Prob. 4.24ECh. 4.5 - Prob. 4.25ECh. 4.6 - Prob. 4.26ECh. 4.6 - Prob. 4.27ECh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. D4.7PCh. 4 - Prob. D4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. D4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. D4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. D4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. D4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. D4.56PCh. 4 - Prob. D4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. D4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. D4.63PCh. 4 - Prob. D4.64PCh. 4 - Prob. D4.65PCh. 4 - Prob. D4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. D4.73PCh. 4 - Prob. D4.74PCh. 4 - Prob. D4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. D4.80PCh. 4 - Prob. D4.81PCh. 4 - Prob. D4.82PCh. 4 - Prob. D4.83PCh. 4 - Prob. D4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88PCh. 4 - Prob. 4.89PCh. 4 - Prob. 4.90PCh. 4 - Prob. 4.91PCh. 4 - Prob. 4.92PCh. 4 - Prob. 4.93PCh. 4 - Prob. 4.94PCh. 4 - Prob. 4.95PCh. 4 - Prob. 4.96PCh. 4 - Prob. 4.97P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- quick reply needed.arrow_forwardDescribe the operating principle and characteristics of a typical Zener diode found in the market place, including examples of their common applications. The circuit shown below is to be used to provide a stabilised output to the load. The Zener diode characteristic is also shown on the next page. Find the load voltage (VL) and source current (IS) if the battery voltage is 18 V, series resistance is 1.4 KΩ and load resistance is 11 KΩ. Additionally, determine the value of the source resistance (R) if the Zener diode is at the threshold of activating in its reverse bias. Comment on the purpose of having this value of R in the circuit.arrow_forward5. For following Zener diode circuit, Vz=-4.5, slope for reverse bias is 40mA/V (a). Find expression for v0 in terms of V and Av (b). Calculate the amount of DC and the amount of AC in the output voltage using the Zener diode characteristic to find model values (mA) vz 8 4 4+ La 2 ½Z (V) R₁ = 1kQ wwww Av50 mV AC V10 V DC 8arrow_forward
- A designer has a supply of diodes for which a current of 2 mA flows at 0.7 V. Using a 1-mA current source, the designer wishes to create a reference voltage of 1.3 V. Suggest a combination of series and parallel diodes that will do the job as best as possible. How many diodes are needed? What voltage is actually supplied?arrow_forwardThe circuit below has a variable voltage vin as its input. We are interested in Vout as a function of Vin. In other words, if we vary the value of the voltage source vin, what will be the effect on the voltage Vout? The steps below will help you to investigate this question, and your answers will form the basis for a new design. Assume that the diode can be sufficiently modelled as simple diode with forward voltage of 0.7 V (you do not need Shockley's equation). Vin 100Ω M Vf = 0.7 V 2 V V outarrow_forward10+ D NAME: The diodes in the circuit below have a saturation current Is = 10-¹4A. The NMOSFET has a threshold voltage of +1V and a K parameter of 10mA/V². > ID = Is (evo/VT - 1) a) Use the exponential diode model b) Oops. Someone built the circuit below, and apparently made a mistake selecting the components. They measure the voltage VA and it is equal to 1.9V. Based on VA = 1.9V, determine the expected value of V₂. +1 -3 V AVD -0.4 3-V 3-2V0 I VA=1.9V 041 VA to calculate VA. 2.2 ΚΩ +10V T 100 Ω NMOSFET VB Ins=4.05marrow_forward
- p4. A biased clamper is connected to a rectangular AC input with 20V on the positive half cycle and -10V on the negative half cycle. The orientation of the Si diode is the same with Vo while the 5V biasing voltage is in opposite connection. The value of R is 100K ohms while the capacitor is 1 microFarad. In P4, what is the voltage across the capacitor? a. 34.3V b. 14.7V c. 24.3V d. 20.7Varrow_forwardIRL RL In the circuit using a Zener diode above, given that V, = 10 V, R= 3.7 KO, R 6.8 KQ, and the Zener voltage Vz = 5 V. a) The current IRL through the load resistor is b) The current fiowing through the resistor R is:arrow_forwardLet’s look at the Wheatstone bridge where antiparallel diodes are place between nodes A and B. Assume the diodes have the following characteristic:arrow_forward
- A silicon diode is in parallel with a germanium diode and is connected to a load resistor having a value of 20 kQ and a forward supply voltage of 10 V. What is the approximate voltage across the silicon diode? * A. 10 V B. 1.0 V C. 0.7 V D. 0.3 Varrow_forwardDetermine the suitable values for resistors R3 and R4 for the regulator in Figure Q4.d. The required output voltage is 7.4V, and the Zener diode voltage is 4.7V. V₁ Ď R₁ R₂ Τ1 R3 H 21 T2 Vp R4 Vz Figure Q4.d V.arrow_forwardVps = 10 V R = 0.1k02 ww -ovo R₁. Consider the Zener diode circuit shown in figure. The Zener diode voltage is Vz= 5.8V at Iz= 10mA and the Zener resistance is rz = 200. a) Find the output voltage for RL = 1k0 b) Find the change in the output voltage when the load resistance varies +ARL.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,