Explanation Given info: The skateboarder starts up a 1.0 m high, the ramp is at 30 ° inclined from the ground and the initial speed of the skateboarder is 7.0 m / s . According to the conservation of the law of energy, the final energy of the skateboarder at the top is equal to the initial energy of the skateboarder. 1 2 m v i 2 = 1 2 m v f 2 + m g h m is the mass of the skateboarder. v i is the initial velocity of the skateboarder. v f is the final velocity of the skateboarder. g is the acceleration due to gravity. h is the final height of the skateboarder. Substitute 7.0 m / s for v i , 9.8 m / s 2 for g and 1.0 m for h to find v f . 1 2 m ( 7.0 m / s ) 2 = 1 2 m v f 2 + m ( 9.8 m / s 2 ) ( 1.0 m ) v f 2 = 49 m 2 / s 2 − 2 × ( 9.8 m 2 / s 2 ) v f = 29.4 = 5.4 m / s Formula to calculate the final vertical position of the skateboarder is y = y 0 + v f sin θ + 1 2 ( − g ) t 2 y is the final vertical position of the skateboarder

Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)

4th Edition

ISBN: 9780134110684

Author: Randall D. Knight (Professor Emeritus)

Publisher: PEARSON

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Chapter 4, Problem 83EAP

To determine

The distance from the end of the ramp at which the skateboarder touches the ground.

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Chapter 4, Problem 82EAP

Chapter 4, Problem 84EAP

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Chapter 4 Solutions

Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)

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