
Concept explainers
(a)
Interpretation:
An open vessel contains water in a laboratory measuring
Concept introduction:
The number of moles of any substance can be determined using the equation
The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mole (g/mol).
Ideal gas equation,
(a)

Explanation of Solution
Given,
An open vessel contains water in a laboratory measuring
Volume of vessel can be determined as follows,
Moles of water in this volume under the given consitions can be determined using Ideal gas equation as follows,
The mass of water can be determined by multiplying this amount of water with its molar mass.
Thus,
(b)
Interpretation:
An open vessel contains benzene in a laboratory measuring
Concept introduction:
The number of moles of any substance can be determined using the equation
The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mole (g/mol).
Ideal gas equation,
(b)

Explanation of Solution
Given,
An open vessel contains benzene in a laboratory measuring
Volume of vessel can be determined as follows,
Moles of benzene in this volume under the given consitions can be determined using Ideal gas equation as follows,
The mass of benzene can be determined by multiplying this amount of benzene with its molar mass.
Thus,
(c)
Interpretation:
An open vessel contains mercury in a laboratory measuring
Concept introduction:
The number of moles of any substance can be determined using the equation
The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mole (g/mol).
Ideal gas equation,
(c)

Explanation of Solution
Given,
An open vessel contains mercury in a laboratory measuring
Volume of vessel can be determined as follows,
Moles of water in this volume under the given consitions can be determined using Ideal gas equation as follows,
The mass of mercury can be determined by multiplying this amount of mercury with its molar mass.
Thus,
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Chapter 4 Solutions
Elements Of Physical Chemistry
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