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Concept explainers
(a)
Interpretation:
The name of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
(b)
Interpretation:
The chemical formula of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
(c)
Interpretation:
The number of ions present in the formula unit of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
(d)
Interpretation:
The number of electrons transferred per formula unit of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
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Chapter 4 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- 1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forward
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
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