(a) Interpretation: The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated. Concept introduction: When an unsymmetrical alkene is reacted with HBr , a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

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Answer 1

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Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when 1-methylcyclopent-1-ene and 1-methylenecyclopentane reacts with DBr is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, an alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

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Answer 2

Question

Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when 1-methylcyclopent-1-ene and 1-methylenecyclopentane reacts with DBr is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, an alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

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Answer 3

Question

Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when 1-methylcyclopent-1-ene and 1-methylenecyclopentane reacts with DBr is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, an alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

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Answer 4

Question

Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when 1-methylcyclopent-1-ene and 1-methylenecyclopentane reacts with DBr is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, an alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

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Answer 5

Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when 1-methylcyclopent-1-ene and 1-methylenecyclopentane reacts with DBr is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, an alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Answer 6

Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Answer 7

Chapter 4, Problem 4.51AP

Interpretation Introduction

(a)

Interpretation:

The two structures from which 1-bromo-1-methylcyclopentane can be formed on addition of HBr are to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, a alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when 1-methylcyclopent-1-ene and 1-methylenecyclopentane reacts with DBr is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, an alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Whether the products will be same or not when 1-methylcyclopent-1-ene and 1-methylenecyclopentane reacts with DBr is to be stated.

Concept introduction:

When an unsymmetrical alkene is reacted with HBr, an alkyl bromide is formed. The substitution of HBr in an alkene takes place by Markovnikov’s rule. According to Markovnikov’s rule, halide is substituted to the carbon atom which bears less number of hydrogen atoms and hydride ion is substituted to the carbon atom which bears more number of hydrogen atoms.

Answer 10

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Answer 13

Ch. 4 - Prob. 4.1P Ch. 4 - Prob. 4.2P Ch. 4 - Prob. 4.3P Ch. 4 - Prob. 4.4P Ch. 4 - Prob. 4.5P Ch. 4 - Prob. 4.6P Ch. 4 - Prob. 4.7P Ch. 4 - Prob. 4.8P Ch. 4 - Prob. 4.9P Ch. 4 - Prob. 4.10P

Solution Summary: The author explains that 1-bromo-1-methylcyclopentane can be formed by the reactions of

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