
Concept explainers
(a)
Interpretation:
The
Concept introduction:

Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 1
In this case, bromide ion gets priority over chloride ion and iodide ion gets priority over chloride ion. The structure with higher priority order is written as shown below.
Figure 2
The higher priority groups are present on opposite sides of the double bond. As a result,
The configuration of the given structure is
(b)
Interpretation:
The
Concept introduction:
Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as

Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 3
In this case, the
Figure 4
The higher priority atoms are present on the same side of the double bond. As a result,
The configuration of the given structure is
(c)
Interpretation:
The
Concept introduction:
Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as

Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 5
In this case, right side of double bond contains
Figure 6
One carbon atom is attached to three carbon atoms and other attached to two carbon atoms. Therefore, the carbon atom which is attached to three carbon atoms gets higher priority. As a result, higher priority atoms are present on opposite sides of the double bond. The structure is assigned
The configuration of the given structure is
(d)
Interpretation:
The
Concept introduction:
Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as

Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 7
In this case, left and right side of the double bond contains a carbon atoms cyclic ring whose priority order is identified on the basis of higher priority order atoms attached to its carbon atom which is marked as shown below.
Figure 8
On both sides, One carbon atom is attached to three carbon atoms and other attached to two carbon atoms. Therefore, the carbon atom which is attached to three carbon atoms gets higher priority. Along with double bond get higher priority over the single bond. As a result, higher priority atoms are present on opposite sides of the double bond. The structure is assigned
The configuration of the given structure is
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Chapter 4 Solutions
Organic Chemistry
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- Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. + More... ☐ ☐ : ☐ + G 1. NaOMe Click and drag to start drawing a structure. 2. H +arrow_forward6. Ammonia reacts with nitrogen monoxide and oxygen to form nitrogen and water vapor. If the rate of consumption of NO is 4.5 mollitermin) (a) Find the rate of reaction (b) Find the rate of formations of N; and HO (c) Find the rate of consumption of NH, and O 4NH: 4NO 0:4: +60arrow_forward34. Give the expected major product of each of the following reactions. Conc. HI a. CH3CH2CH2OH b. (CH3)2CHCH2CH2OH Conc. HBr H Conc. HI C. OH Conc.HCI d. (CH3CH2)3COHarrow_forward
- 42. Which of the following halogenated compounds can be used successfully to prepare a Grignard reagent for alcohol synthesis by subsequent reaction with an aldehyde or ketone? Which ones cannot and why? H3C CH3 a. Br H OH b. Cl C. I H H d. Cl e. H OCH3 Br Harrow_forwardFor each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? Will the first MgBr product that forms in this reaction create a new CC bond? olo ? OH جمله O Yes Ⓒ No MgCl ? Will the first product that forms in this reaction create a new CC bond? Click and drag to start drawing a structure. Yes No X ☐ : ☐ टे PHarrow_forwardAssign all the protonsarrow_forward
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