(a)
Interpretation:
The volume of 1.222 M sodium hydroxide which is required to react with 32.5 mL of 0.569 M sulfurous acid should be calculated.
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
(b)
Interpretation:
The volume of 1.222 M sodium hydroxide which is required to react with 2.00 g of oxalic acid should be calculated.
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
(c)
Interpretation:
The volume of 1.222 M sodium hydroxide which is required to react 15.0 g of concentrated acetic acid which is 88% by mass pure should be calculated.
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
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Chapter 4 Solutions
Chemistry: Principles and Reactions
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- On Easter Sunday, April 3, 1983, nitric acid spilled from a tank car near downtown Denver, Colorado. The spill was neutralized with sodium carbonate: 2HNO3(aq)+Na2CO3(aq)2NaNO3(aq)+H2O(l)+CO2(g) a. Calculate H for this reaction. Approximately 2.0 104 gal nitric acid was spilled. Assume that the acid was an aqueous solution containing 70.0% HNO3 by mass with a density of 1.42 glcm3. What mass of sodium carbonate was required for complete neutralization of the spill, and what quantity of heat was evolved? (Hf for NaNO3(aq) = 467 kJ/mol) b. According to The Denver Post for April 4, 1983, authorities feared that dangerous air pollution might occur during the neutralization. Considering the magnitude of H, what was their major concern?arrow_forwardBone was dissolved in hydrochloric acid, giving 50.0 mL of solution containing calcium chloride, CaCL2. To precipitate the calcium ion from the resulting solution, an excess of potassium oxalate was added. The precipitate of calcium oxalate, CaC2O4, weighed 1.437 g. What was the molarity of CaCl2 in the solution?arrow_forwardA stock solution of potassium dichromate, K2Cr2O7, is made by dissolving 84.5 g of the compound in 1.00 L of solution. How many milliliters of this solution are required to prepare 1.00 L of 0.150 M K2Cr2O7?arrow_forward
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