Chapter 4, Problem 126AP

Interpretation Introduction

Interpretation:

The mass of rust that can be removed by the given amount of oxalic acid is to be calculated.

Concept introduction:

The total number of moles of solute present in one-liter solution is termed as molarity.

The mass of compound in the given reaction is calculated by comparing the number of moles of products and reactants.

The conversion of volume from $\text{mL}$ into liter is done as,

$1\text{mL}={10}^{-3}\text{L}$

Number of mole of solute and Molarity of solute can calculated as:

$\begin{array}{c}\text{Molarity of solute (M)}=\frac{\text{moles of solute (n)}}{\text{volume of solution (V)}}\\ \text{n}=\text{MV}\end{array}$