Physics for Scientists and Engineers with Modern Physics
4th Edition
ISBN: 9780131495081
Author: Douglas C. Giancoli
Publisher: Addison-Wesley
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Question
Chapter 39, Problem 34P
To determine
The binding energy of the third electron in lithium using Bohr energy.
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Students have asked these similar questions
(a)
The Lyman series in hydrogen is the transition from energy levels n = 2, 3, 4, ...
to the ground state n =
1. The energy levels are given by
13.60 eV
En
n-
(i)
What is the second longest wavelength in nm of the Lyman series?
(ii)
What is the series limit of the Lyman series?
[1 eV = 1.602 x 1019 J, h = 6.626 × 10-34 J.s, c = 3 × 10° m.s]
%3D
Two emission lines have wavelengts A and + A2, respectively, where AA <<2.
Show that the angular separation A0 in a grating spectrometer is given
aproximately by
(b)
A0 =
V(d/m)-2
where d is the grating constant and m is the order at which the lines are observed.
(i) Using Bohr model for atomic hydrogen, obtain energy levels for the 2s, 3s and 3p states in the
actual number with the unit of [eV]. We consider a transition that electron in the 3p state emits
a photon and make a transition to the 2s state. What is the frequency v of this photon ?
(ii) Now we do not include electron spin angular momentum, and just estimate an effect of a
magnetic field B on this transition (Normal Zeeman effect) with orbital angular momentum.
How many lines of optical transition do we expect ? What is the interval of the frequency in the
field B = 0.1 Tesla ?
(iii) In this situation, we do not expect transition from 3s to 2s state if the electron is initially in the
3s state, Explain the reason.
(iv) We now consider an effect of magnetic field B to a free electron spin (not in Hydrogen, but a
free electron). The magnetic field of B = 1.0 Tesla will split the energy level into two (Zeeman)
levels. Obtain the level difference in the unit of [eV] from the value of…
(6) (a) Show that the speed of an electron in the nth Bohr orbit of hydrogen is ac/n where a is the
fine structure constant.
(b) What would be the speed in a hydrogenlike atom with a nuclear charge of Ze?
Chapter 39 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 39.2 - Prob. 1AECh. 39.2 - Prob. 1BECh. 39.3 - Prob. 1CECh. 39.4 - Prob. 1DECh. 39.4 - Prob. 1EECh. 39.5 - Prob. 1FECh. 39.7 - Prob. 1GECh. 39 - Prob. 1QCh. 39 - Prob. 2QCh. 39 - Prob. 3Q
Ch. 39 - Prob. 4QCh. 39 - Prob. 5QCh. 39 - Prob. 6QCh. 39 - Prob. 7QCh. 39 - Prob. 8QCh. 39 - Prob. 9QCh. 39 - Prob. 10QCh. 39 - Prob. 11QCh. 39 - On what factors does the periodicity of the...Ch. 39 - Prob. 13QCh. 39 - Prob. 14QCh. 39 - Prob. 15QCh. 39 - Prob. 16QCh. 39 - Prob. 17QCh. 39 - Prob. 18QCh. 39 - Prob. 19QCh. 39 - Prob. 20QCh. 39 - Prob. 21QCh. 39 - Prob. 22QCh. 39 - Prob. 23QCh. 39 - Prob. 24QCh. 39 - Prob. 25QCh. 39 - Prob. 26QCh. 39 - Prob. 27QCh. 39 - Prob. 28QCh. 39 - Prob. 29QCh. 39 - Prob. 1PCh. 39 - Prob. 2PCh. 39 - Prob. 3PCh. 39 - Prob. 4PCh. 39 - Prob. 5PCh. 39 - Prob. 6PCh. 39 - Prob. 7PCh. 39 - Prob. 8PCh. 39 - Prob. 9PCh. 39 - Prob. 10PCh. 39 - Prob. 11PCh. 39 - Prob. 12PCh. 39 - Prob. 13PCh. 39 - Prob. 14PCh. 39 - Prob. 15PCh. 39 - Prob. 16PCh. 39 - Prob. 17PCh. 39 - Prob. 18PCh. 39 - Prob. 19PCh. 39 - Prob. 20PCh. 39 - Prob. 21PCh. 39 - Prob. 22PCh. 39 - Prob. 23PCh. 39 - Prob. 24PCh. 39 - Prob. 25PCh. 39 - Prob. 26PCh. 39 - Prob. 27PCh. 39 - Prob. 28PCh. 39 - Prob. 29PCh. 39 - Prob. 30PCh. 39 - Prob. 31PCh. 39 - Prob. 32PCh. 39 - Prob. 33PCh. 39 - Prob. 34PCh. 39 - Prob. 35PCh. 39 - Prob. 36PCh. 39 - Prob. 37PCh. 39 - Prob. 38PCh. 39 - Prob. 39PCh. 39 - Prob. 40PCh. 39 - Prob. 41PCh. 39 - Prob. 42PCh. 39 - Prob. 43PCh. 39 - Prob. 44PCh. 39 - Prob. 45PCh. 39 - Prob. 46PCh. 39 - Prob. 47PCh. 39 - Prob. 48PCh. 39 - Prob. 49PCh. 39 - Prob. 50PCh. 39 - Prob. 51PCh. 39 - Prob. 52PCh. 39 - Prob. 53PCh. 39 - Prob. 54PCh. 39 - Prob. 55PCh. 39 - Prob. 56PCh. 39 - Prob. 57PCh. 39 - Prob. 58PCh. 39 - Prob. 59PCh. 39 - Prob. 60PCh. 39 - Prob. 61GPCh. 39 - Prob. 62GPCh. 39 - Prob. 63GPCh. 39 - Prob. 64GPCh. 39 - Prob. 65GPCh. 39 - Prob. 66GPCh. 39 - Prob. 67GPCh. 39 - Prob. 68GPCh. 39 - Prob. 69GPCh. 39 - Prob. 70GPCh. 39 - Prob. 71GPCh. 39 - Prob. 72GPCh. 39 - Prob. 73GPCh. 39 - Prob. 74GPCh. 39 - Prob. 75GPCh. 39 - Prob. 76GPCh. 39 - Prob. 77GP
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- . (II) Estimate the wavelength for an n = 3 to n = 2 transition in iron (Z = 26).arrow_forward(II) For each of the following atomic transitions, state whether the transition is allowed or forbidden, and why: (a) 4p → 3p; (b) 3p → 1s; (c) 4d → 2d; (d) 5d → 3s; (e) 4s → 2p.arrow_forwardIf the magnetic dipole moment of an atom is 1*10 ^24J/T, then this atom has a magnetic field of 10 Thow much does the potential energy change when placed?arrow_forward
- The ionization (binding) energy of the outermost electronin boron is 8.26 eV. (a) Use the Bohr model to estimate the“effective charge,”Zeff seen by this electron. (b) Estimatethe average orbital radius.arrow_forward(i) Using Bohr model for atomic hydrogen, obtain energy levels for the 2s, 3s and 3p states in theactual number with the unit of [eV]. We consider a transition that electron in the 3p state emitsa photon and make a transition to the 2s state. What is the frequency ν of this photon ?(ii) Now we do not include electron spin angular momentum, and just estimate an effect of amagnetic field B on this transition (Normal Zeeman effect) with orbital angular momentum.How many lines of optical transition do we expect ? What is the interval of the frequency in thefield B = 0.1 Tesla ?(iii) In this situation, we do not expect transition from 3s to 2s state if the electron is initially in the3s state, Explain the reason.(iv) We now consider an effect of magnetic field B to a free electron spin (not in Hydrogen, but afree electron). The magnetic field of B = 1.0 Tesla will split the energy level into two (Zeeman)levels. Obtain the level difference in the unit of [eV] from the value of magnetic…arrow_forward(2) In this experiment, why couldn't we observe the series of spectral lines that arise from electrons falling to the ground state, nfinal = 1? This is the Lyman series, for which 22 (see eq. (16)) must be replaced by 12 in both the numerator and denominator of the equation: 2 =- 1 n2 n = R (n2-1)' 2,3,4,5, ..arrow_forward
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