DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 38, Problem 66RQ
Why is flux removal a necessary part of many brazing operations?
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Chapter 38 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 38 - What are some joining conditions where welding...Ch. 38 - What are some of the lower-temperature methods of...Ch. 38 - In what ways is a thermit weld similar to the...Ch. 38 - What is the source of the welding heat in thermit...Ch. 38 - For what types of applications might thermit...Ch. 38 - What is the source of the welding heat in...Ch. 38 - What are some of the various functions of the slag...Ch. 38 - Electroslag welding would be most attractive for...Ch. 38 - What is the source of heat in electron-beam...Ch. 38 - Why is a high vacuum required in the electron-beam...
Ch. 38 - What types of production limitations are imposed...Ch. 38 - What are the major assets and negative features of...Ch. 38 - What are some of the attractive features of...Ch. 38 - What is unique about the fusion zone geometry of...Ch. 38 - Describe the weld pool geometry and size of the...Ch. 38 - What is an autogenous weld?Ch. 38 - What might be necessary to permit the laser...Ch. 38 - What are some of the Ways in which laser-beam...Ch. 38 - What are the three common types of industrial...Ch. 38 - Which type of laser light can be transmitted...Ch. 38 - What are some of the attractive features of a...Ch. 38 - Why is laser-beam welding an attractive process...Ch. 38 - What are the attractive properties of hybrid...Ch. 38 - Prob. 24RQCh. 38 - What is the function of the assist gas in...Ch. 38 - What is the difference between exothermic cutting...Ch. 38 - Which type of laser is preferred for cutting...Ch. 38 - Prob. 28RQCh. 38 - Prob. 29RQCh. 38 - What features have made lasers a common means of...Ch. 38 - What are some of the attractive features of laser...Ch. 38 - What are some common objectives of surfacing...Ch. 38 - What types of materials are applied by surfacing...Ch. 38 - Prob. 34RQCh. 38 - What is the benefit of high-velocity oxyfuel...Ch. 38 - What are some of the arc or plasma techniques that...Ch. 38 - How is thermal spraying similar to surfacing? How...Ch. 38 - Prob. 38RQCh. 38 - Prob. 39RQCh. 38 - Provide a reasonable definition of brazing?Ch. 38 - What are some key differences between brazing and...Ch. 38 - What kinds of materials or combinations can be...Ch. 38 - What advantages can be gained by the lower...Ch. 38 - Why do brazed joints have an enhanced...Ch. 38 - What is the most important factor influencing the...Ch. 38 - How does capillary action relate to joint...Ch. 38 - Why is it necessary to adjust the initial...Ch. 38 - What is wettability? Fluidity? How do each relate...Ch. 38 - What are the two most common types of brazed...Ch. 38 - How do the butt-lap and scarf joint configurations...Ch. 38 - What are some important considerations when...Ch. 38 - What are some of the most commonly used brazing...Ch. 38 - Why are eutectic alloys attractive as brazing...Ch. 38 - What special measures should be taken when brazing...Ch. 38 - What are the three primary functions of a brazing...Ch. 38 - Why is it important to preclean brazing surfaces...Ch. 38 - How might braze metal be preloaded into joints?Ch. 38 - What is the purpose of brazing jigs and fixtures?Ch. 38 - 59- What are some factors to consider when...Ch. 38 - What are the advantages and disadvantages of torch...Ch. 38 - What is the primary attraction of furnace-brazing...Ch. 38 - Why might reducing atmospheres or a vacuum be...Ch. 38 - What are some of the attractive features of...Ch. 38 - Why is dip brazing usually restricted to use with...Ch. 38 - What are some of the attractive features of...Ch. 38 - Why is flux removal a necessary part of many...Ch. 38 - What benefits can be achieved through fluxless...Ch. 38 - How does braze welding differ from traditional...Ch. 38 - What is the primary difference between brazing and...Ch. 38 - What are the six steps of a soldering operation?Ch. 38 - Why is soldering unattractive if a high-strength...Ch. 38 - For many years, the most common solders have been...Ch. 38 - What is driving the conversion to lead-free...Ch. 38 - What are some of the difficulties encountered when...Ch. 38 - What are the two basic families of soldering flux?Ch. 38 - What are some of the more common heat sources for...Ch. 38 - Why is wave soldering attractive for making the...Ch. 38 - Describe the vapor-phase soldering process.Ch. 38 - A common problem with brazed or soldered joints is...Ch. 38 - When molten metal deposition is applied to a...Ch. 38 - Prob. 3P
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- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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- Problem 5: Three-Force Equilibrium A structural connection at point O is in equilibrium under the action of three forces. • • . Member A applies a force of 9 kN vertically upward along the y-axis. Member B applies an unknown force F at the angle shown. Member C applies an unknown force T along its length at an angle shown. Determine the magnitudes of forces F and T required for equilibrium, assuming 0 = 90° y 9 kN Aarrow_forwardProblem 19: Determine the force in members HG, HE, and DE of the truss, and state if the members are in tension or compression. 4 ft K J I H G B C D E F -3 ft -3 ft 3 ft 3 ft 3 ft- 1500 lb 1500 lb 1500 lb 1500 lb 1500 lbarrow_forwardProblem 14: Determine the reactions at the pin A, and the tension in cord. Neglect the thickness of the beam. F1=26kN F2 13 12 80° -2m 3marrow_forward
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