Explanation Given info: The transmission coefficient for diamond and air is 0.828 from the problem 38 . The total amount transmitted from problem 37 is, T t = T 2 + T 2 ( 1 − T ) 2 + T 2 ( 1 − T ) 4 + T 2 ( 1 − T ) 6 + … + T 2 ( 1 − T ) 2 n + … Substitute 0.828 for T in the above equation. T t = [ ( 0.828 ) 2 + ( 0.828 ) 2 ( 1 − 0.828 ) 2 + ( 0.828 ) 2 ( 1 − 0.828 ) 4 + ( 0.828 ) 2 ( 1 − 0.828 ) 6 + … + ( 0.828 ) 2 ( 1 − 0.828 ) 2 n + … ] = ( 0.828 ) 2 [ 1 + ( 0.172 ) 2 + ( 0.172 ) 4 + ( 0.172 ) 6 + … ] (1) Now, the series is, F = 1 + ( 0.172 ) 2 + ( 0.172 ) 4 + ( 0.172 ) 6 + … (2) Substitute 1 + ( 0.172 ) 2 + ( 0.172 ) 4 + ( 0.172 ) 6 + ( 0.172 ) 8 + … for F in equation (1)

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Dispersion of White Light

Snell’s law is a formula that gives a relation between the angle of incidence and angle of refraction and is given as:

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Chapter 35, Problem 35.87CP

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The fraction of the intensity of the transmitted light in the incident intensity.

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Chapter 35, Problem 35.86CP

Chapter 36, Problem 36.1QQ

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The fraction of the intensity of the transmitted light in the incident intensity.

Solution Summary: The author explains that the transmission coefficient for diamond and air is 0.828 from the problem 38.

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The fraction of the intensity of the transmitted light in the incident intensity.

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Chapter 35 Solutions