Chapter 3.4, Problem 4CYU

To determine

To write in point-slope form for the line that having the given slope that contains the given point point.Then graph.

  $m:5$

  $(3,-2)$

Answer to Problem 4CYU

Slope intercept form

  $y=\text{ 4}x-14$

Graph

Explanation of Solution

Given information:

The line having slope and point

  $m:5$

  $(3,-2)$

Formula used:

Point-slope form

  $y-y_1=m(x-x_1)$

Calculation:

The line having slope and point

  $m:5$

  $(3,-2)$

Here

  $x_1=3$

  $y_1=-2$

The general point-slope form is given as

  $y-y_1=m(x-x_1)$

Where

  $m$ is slope

Substitute value of slope and point in general point-slope form

  $y-(-2)=\text{ 4}(x-3)$

On solving

  $y+2=\text{ 4}(x-3)$

On solving

  $y+2=\text{ 4}x-12$

On solving

  $y=\text{ 4}x-14$

Substituting $x=0$

Then

  $y=-14$

Substituting $y=0$

Then

  $\text{ 0 }=\text{ 4}x-14$

On solving

  $x=\frac{7}{2}$

Table

Then graph