Chapter 3.2, Problem 6PP

Interpretation Introduction

Interpretation:

The amount of water involved in this process calculated.

Concept introduction:

In a chemical reaction the mass of product and reactant will not change, only the rearrangements of the molecules will take place. The amount of reactant is equals to the amount of the product, and follows the law of conservation of mass.

Answer to Problem 6PP

The amount of water involved in this process is $\text{89}\text{.4}\text{g}$.

Explanation of Solution

The given mass of the hydrogen is $\text{10}\text{.0}\text{g}$ and mass of oxygen is $\text{79}\text{.4}\text{g}$ ,

So for the amount of water −

Mass of product = Mass of reactant

Mass of product = mass of hydrogen $+$ mass of oxygen

Mass of water = mass of hydrogen $+$ mass of oxygen

$\text{=10}\text{.0}\text{g}\text{+}\text{79}\text{.4}\text{g}\text{=}\text{89}\text{.4}\text{g}$

Conclusion

From the given amount of hydrogen and oxygen, the amount of water is easy to calculate because the water molecule is the composition of the hydrogen and oxygen.