Chapter 3.2, Problem 7PP

Interpretation Introduction

Interpretation:

The amount of chlorine gas involved in the reaction needs to be determined.

Concept introduction:

In a chemical reaction the mass of product and reactant will not change, only the rearrangements of the molecules will take place. The amount of reactant is equals to the amount of the product, and follows the law of conservation of mass.

Answer to Problem 7PP

The amount of chlorine gas involved in the reaction is $\text{24}\text{.1}\text{g}$, and $\text{15}\text{.6}\text{g}$ sodium used for this reaction.

Explanation of Solution

The mass of the sodium is $\text{15}\text{.6}\text{g}$ and the formed sodium chloride is $\text{39}\text{.7}\text{g}$

So for the amount of chlorine gas participated in the reaction-

Mass of product = Mass of reactant

Mass of product = mass of sodium $+$ mass of chlorine

Mass of sodium chloride = mass of sodium $+$ mass of chlorine

For the calculation of mass of chlorine

Mass of chlorine = Mass of sodium chloride $-$ Mass of sodium

$=\text{39}\text{.7}\text{g}\text{-}\text{15}\text{.6}\text{g}\text{ =}\text{24}\text{.1}\text{g}$

The amount of chlorine is $\text{24}\text{.1}\text{g}$.

The amount of sodium $\text{15}\text{.6}\text{g}$ is used in the reaction.

Conclusion

From the given amount of sodium and sodium chloride, the amount of chlorine is easy to calculate because chlorine gas participated in the formation of the sodium chloride.