Chapter 32, Problem 45PE

(a) Calculate the energy released in the neutron−induced fission reaction

$n{+}^{239}\text{Pu}{\to }^{96}\text{Sr}{+}^{140}\text{Ba+4}n$,

given $m\left({}^{96}\text{Sr}\right)=95.921750\text{u}$ and

$m\left({}^{140}\text{Ba}\right)=139.910581\text{u}$.

(b) Confirm that the total number of nucleons and total charge are conserved in this reaction.