Concept explainers
What’s your favorite TV show? The following table presents the rating for the top 20 prime time shows for the 2007 -2008 season and for the 2012 -2013 season. The rating is the percentage of households with TV sets watched the program
- Find the population standard deviation of the ratings for 2007—2008.
- Find the population standard deviation of the ratings for 2012—2013.
- Compute the
range for the ratings for both seasons. - Based on the standard deviations, did the spread in ratings increase or decrease over the two seasons?
- Based on the ranges, did the spread in ratings increase or decrease over the two seasons?
(a)
To find the population standard deviation for 2007 − 2008.
Answer to Problem 35E
The population standard deviation of the ratings for
Explanation of Solution
Given information:
Top Rated TV programs:
Programs | Rating |
American Idol −− Tuesday | |
American Idol −− Wednesday | |
Dancing With the Star −− Monday |
|
Dancing With the Star −− Tuesday |
|
Dancing With the Star −− Monday |
|
Dancing With the Star −− Tuesday |
|
Desperate Housewives | |
CIS | |
House −− Tuesday | |
Grey’s Anatomy | |
Sunday Night Football | |
CIS: Miami | |
House −− Monday | |
NCIS | |
Survivor: China | |
Without a Trace | |
The Moment of Truth | |
Two and a Half Men | |
|
|
Criminal Minds | |
Top Rated TV Programs: 2012-2013
Programs | Rating |
NBC Sunday Night Football | 7.9 |
Bing Bang Theory | 6.2 |
The Voice | 5.1 |
Modern Family | 4.9 |
The Voice- Tuesday | 4.6 |
American Idol -Wednesday | 4.6 |
American Idol -Thursday | 4.3 |
The Following | 4.3 |
Two and a Half Men | 4.1 |
Grey's Anatomy | 4.1 |
NCIS | 4.0 |
Football Night in American Part 3 | 4.0 |
Revolution | 3.9 |
2 Broke Girls | 3.7 |
How I Met Your Mother | 3.7 |
Family Guy | 3.6 |
Once Upon a Time | 3.6 |
Survivor- Philippines | 3.5 |
X-Factor - Wednesday | 3.5 |
NCIS : LA | 3.4 |
Concept used:
Following steps of TI-83 calculator are used to calculate the population standard deviation.
- Click on STAT > Edit
- Enter the provided data in L1.
- Press STAT > CALC > 1-Var Stats
- Enter L1 by pressing 2nd and 1.
- Press Enter.
Calculation:
Using the above mentioned step of TI-83 calculator, the obtained output is:
Thus, the population standard deviation
(b)
To calculate the population standard deviation for 2012 − 2013.
Answer to Problem 35E
The population standard deviation of the ratings for year
Explanation of Solution
Calculation:
Using the TI-83 calculator, the obtained output is:
Thus, the population standard deviation of the ratings for
(c)
To calculate the range for both years.
Answer to Problem 35E
The range of the ratings for
The range of the ratings for
Explanation of Solution
The range of the set of data is the difference between the largest and smallest values of the data.
The range is calculated as:
The range of the ratings for the year 2007-2008 can be calculated as:
Similarly, the range of the ratings for the year 2012-2013 can be calculated as:
Thus, the range of the ratings for the years 2007-2008 and 2012-2013 are 7.9 and 4.5 respectively.
(d)
To explain whether the spread increases or decrease over the two seasons based on standard deviation.
Answer to Problem 35E
Yes, there is a decrease in spread ove.r the two seasons
Explanation of Solution
The population standard deviation of the ratings for
The population standard deviation of the ratings for
Based on the population standard deviation, the spread in ratings has decreased over the two seasons.
(e)
To explain whether the spread increase or decrease over the two seasons based on the range.
Answer to Problem 35E
Based on the ranges, the spread in ratings decrease over the two seasons
Explanation of Solution
The range of the ratings for
The range of the ratings for
Based on the ranges, the spread in ratings decrease over the two seasons
Want to see more full solutions like this?
Chapter 3 Solutions
Elementary Statistics (Text Only)
- 30. An individual who has automobile insurance from a certain company is randomly selected. Let Y be the num- ber of moving violations for which the individual was cited during the last 3 years. The pmf of Y isy | 1 2 4 8 16p(y) | .05 .10 .35 .40 .10 a.Compute E(Y).b. Suppose an individual with Y violations incurs a surcharge of $100Y^2. Calculate the expected amount of the surcharge.arrow_forward24. An insurance company offers its policyholders a num- ber of different premium payment options. For a ran- domly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: F(x)=0.00 : x < 10.30 : 1≤x<30.40 : 3≤ x < 40.45 : 4≤ x <60.60 : 6≤ x < 121.00 : 12≤ x a. What is the pmf of X?b. Using just the cdf, compute P(3≤ X ≤6) and P(4≤ X).arrow_forward59. At a certain gas station, 40% of the customers use regular gas (A1), 35% use plus gas (A2), and 25% use premium (A3). Of those customers using regular gas, only 30% fill their tanks (event B). Of those customers using plus, 60% fill their tanks, whereas of those using premium, 50% fill their tanks.a. What is the probability that the next customer will request plus gas and fill the tank (A2 B)?b. What is the probability that the next customer fills the tank?c. If the next customer fills the tank, what is the probability that regular gas is requested? Plus? Premium?arrow_forward
- 38. Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities .15, .35, .35, and .15, respectively. a. Calculate E(X) and then E(5 - X).b. Would the repair facility be better off charging a flat fee of $75 or else the amount $[150/(5 - X)]? [Note: It is not generally true that E(c/Y) = c/E(Y).]arrow_forward74. The proportions of blood phenotypes in the U.S. popula- tion are as follows:A B AB O .40 .11 .04 .45 Assuming that the phenotypes of two randomly selected individuals are independent of one another, what is the probability that both phenotypes are O? What is the probability that the phenotypes of two randomly selected individuals match?arrow_forward53. A certain shop repairs both audio and video compo- nents. Let A denote the event that the next component brought in for repair is an audio component, and let B be the event that the next component is a compact disc player (so the event B is contained in A). Suppose that P(A) = .6 and P(B) = .05. What is P(BA)?arrow_forward
- 26. A certain system can experience three different types of defects. Let A;(i = 1,2,3) denote the event that the sys- tem has a defect of type i. Suppose thatP(A1) = .12 P(A) = .07 P(A) = .05P(A, U A2) = .13P(A, U A3) = .14P(A2 U A3) = .10P(A, A2 A3) = .011Rshelfa. What is the probability that the system does not havea type 1 defect?b. What is the probability that the system has both type 1 and type 2 defects?c. What is the probability that the system has both type 1 and type 2 defects but not a type 3 defect? d. What is the probability that the system has at most two of these defects?arrow_forwardThe following are suggested designs for group sequential studies. Using PROCSEQDESIGN, provide the following for the design O’Brien Fleming and Pocock.• The critical boundary values for each analysis of the data• The expected sample sizes at each interim analysisAssume the standardized Z score method for calculating boundaries.Investigators are evaluating the success rate of a novel drug for treating a certain type ofbacterial wound infection. Since no existing treatment exists, they have planned a one-armstudy. They wish to test whether the success rate of the drug is better than 50%, whichthey have defined as the null success rate. Preliminary testing has estimated the successrate of the drug at 55%. The investigators are eager to get the drug into production andwould like to plan for 9 interim analyses (10 analyzes in total) of the data. Assume thesignificance level is 5% and power is 90%.Besides, draw a combined boundary plot (OBF, POC, and HP)arrow_forwardPlease provide the solution for the attached image in detailed.arrow_forward
- Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin HarcourtHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill