Explanation Given info: The given two wavelengths are 656.3 nm and 486.1 nm . The spacing between the slits are 1.667 μm . Write the formula for maxima in multiple slit interference system. d sin θ = m λ Here, d is the distance between the slits θ is the angular position m is the order λ is the wavelength Re-write the above formula to get an expression for θ . θ = sin − 1 ( m λ d ) Substitute 1.667 μm for d , 2 for m 656.3 nm to determine the second order angular separation for wavelength 656.3 nm . θ = sin − 1 ( 2 ( 656

Essential University Physics (3rd Edition)

3rd Edition

ISBN: 9780134202709

Author: Richard Wolfson

Publisher: PEARSON

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Chapter 32, Problem 20E

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The second-order angular separation of the two wavelengths 656.3 nm and 486.1 nm .

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Chapter 32, Problem 19E

Chapter 32, Problem 21E

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Chapter 32 Solutions

Essential University Physics (3rd Edition)

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The second-order angular separation of the two wavelengths 656.3 nm and 486.1 nm .

Solution Summary: The author explains the second-order angular separation of the two wavelengths, 656.3nm and 486.1. The spacing between the slits is 1.667.

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The second-order angular separation of the two wavelengths 656.3 nm and 486.1 nm .

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Chapter 32 Solutions