Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 76 01 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Question

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Answer 1

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

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Answer 2

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Answer 8

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 9

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 10

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 11

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 12

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Answer 13

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Answer 14

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Answer 15

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Answer 16

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Answer 17

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

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Check out a sample textbook solution

See solution

Answer 21

Ch. 3.4 - Prob. 3.1PP Ch. 3.4 - Prob. 3.2PP Ch. 3.4 - Prob. 3.3PP Ch. 3.4 - Prob. 3.4PP Ch. 3.4 - Prob. 3.5PP Ch. 3.5 - Prob. 3.6PP Ch. 3.5 - Prob. 3.7PP Ch. 3.5 - Prob. 3.8PP Ch. 3.5 - Prob. 3.9PP Ch. 3.5 - Prob. 3.10PP

Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 76 01 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Solution Summary: The author explains that each box in table represents 8 bytes. The hexadecimal values are stored inside table.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Want to see the full answer?

Chapter 3 Solutions

Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 76 01 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Solution Summary: The author explains that each box in table represents 8 bytes. The hexadecimal values are stored inside table.

Explanation of Solution

Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 7601 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Explanation of Solution

Stack after line 5: The stack details are shown below: 00 00 00 00 00 40 00 3433 32 31 30 39 38 37 3635 34 33 32 31 30 39 3837 36 35 34 33 32 31 30 Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Explanation of Solution

Address of program return: The program attempts to return to address “0x040034”. The low-order 2 bytes ...

Explanation of Solution

Registers with corrupted values: The register “%rbx” has saved value that is set to “0x3332313039383736”...

Explanation of Solution

Error in get_line code: The call to “malloc” method has argument “strlen(buf)”. The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Want to see the full answer?

Chapter 3 Solutions

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...